SQL

Question

我在这个查询中尝试将查询输出存储到 @json 变量中，但出现语法错误

DECLARE @json NVARCHAR(MAX)

SELECT @json = (JSON_QUERY((SELECT 
                                'Ball' AS title, 
                                'Blue' AS color, 
                                (SELECT 
                                     '1' AS Opt1, 
                                     '2' AS Opt2 
                                 FOR JSON PATH) AS Options
                            FOR JSON PATH, WITHOUT_ARRAY_WRAPPER)) AS Product
FOR JSON PATH, WITHOUT_ARRAY_WRAPPER;)

SELECT @json

错误：

Msg 156, Level 15, State 1, Line 11
Incorrect syntax near the keyword 'AS'.

我该怎么做？

Answer 1

在 VBokšić 的 link 之后，我将此查询作为答案：

DECLARE @json NVARCHAR(MAX)

SET @json = (SELECT (JSON_QUERY((
    SELECT 'Ball' AS title, 
           'Blue' AS color, (
                SELECT '1' AS Opt1, 
                       '2' AS Opt2 
                FOR JSON PATH
           ) AS Options
    FOR JSON PATH, WITHOUT_ARRAY_WRAPPER
    ))) AS product
FOR JSON PATH, WITHOUT_ARRAY_WRAPPER)

SELECT @json

输出：

{"product":{"title":"Ball","color":"Blue","Options":[{"Opt1":"1","Opt2":"2"}]}}

SQL - 如何将 JSON_QUERY 输出存储到变量

SQL - How to store JSON_QUERY output to variable

tsql

json

sql-server-2016