如何创建一个 returns 有问题的值（键）的字典？

Question

我必须创建一个字典（在你的文件中），其中包含我课程中的四个人以及他们所属小组的名称。当我运行我的程序时，它应该要求用户输入一个名字，然后 return 那个人的组名返回给他们。它应该看起来像这样：

Welcome to the py-group-infromator, I can tell you where those users belong to:
{name_user}
{name_user}
{name_user}
{name_user}
Which user do you want to ask for?
{name_user}
{name_group}

开头

notes = ''' "Welcome to the py-group-informator,
    I can tell you where those users belong to" :
    Azura
    Mate
    Anna 
    John 
    " Which user do you want to ask for ?" '''
print(notes)

我的字典

people = [{'name': "Azura", 'group': "cute_python"},{'name': "Mate", 'group': "cute_python"},{'name': "Anna", 'group': "fatal_error"},{'name': "John", 'group': "fatal_error"}]

有什么可以帮助我的吗？非常抱歉我的风格，这是我的第一个问题 ;)

Answer 1

试试这个：

people = [
    {'name': "Azura", 'group': "cute_python"},
    {'name': "Mate", 'group': "cute_python"},
    {'name': "Anna", 'group': "fatal_error"}, 
    {'name': "John", 'group': "fatal_error"}
]

def op(names):
    for value in people:
        if value['name'].lower() in names.lower():
            print(value['group'])

x = op(input("Welcome to the py-group-information,I can tell you where 
    those users belong to : Azura Mate  Anna   John Which user do you want 
    to ask for ?"))

Answer 2

与其他答案类似，但我会写得有点不同：

people = [
    {'name': "Azura", 'group': "cute_python"},
    {'name': "Mate", 'group': "cute_python"},
    {'name': "Anna", 'group': "fatal_error"}, 
    {'name': "John", 'group': "fatal_error"}
]
name_to_group = {d['name']: d['group'] for d in people}

print("Group Information")
names = ', '.join(name_to_group)
name = input(f"Enter one of {names} or 0 to exit: ")
while name != '0':
    if name not in name_to_group:
        continue
    print(f"{name} is in group {name_to_group[name]}")
    name = input(f"Enter one of {names} or 0 to exit: ")
print('Good Bye')

示例输出：

Group Information
Enter one of Azura, Mate, Anna, John or 0 to exit: Mate
Mate is in group cute_python
Enter one of Azura, Mate, Anna, John or 0 to exit: John
John is in group fatal_error
Enter one of Azura, Mate, Anna, John or 0 to exit: 0
Good Bye

Answer 3

以下是从您的数据结构中提取的核心逻辑（有意省略您的列表和欢迎屏幕文本）。假设你有这些，首先捕获用户输入如下，然后继续搜索他们所属的组。

user_name = input("Which user do you want to ask for ?")
    for item in people:
        for key in item:
            if item[key] == user_name:
                    print(item['group'])
                    break

如何创建一个 returns 有问题的值（键）的字典？

How to create a dictionary that returns the value(key) in question?

python

dictionary

return-value

python-3.x