跨两个模型的 Django 简单注释
Django simple annotation across two models
我有三个模型,User、Achievement 和 UserAchievement:
class User(AbstractUser):
email = models.EmailField(_('email address'), unique=True)
...
class Achievement(models.Model):
name = models.CharField(max_length=64)
points = models.PositiveIntegerField(default=1)
class UserAchievement(models.Model):
# Use a lazy reference to avoid circular import issues
user = models.ForeignKey('users.User', on_delete=models.CASCADE)
achievement = models.ForeignKey(Achievement, on_delete=models.CASCADE)
我想用一个 'points' 列来注释用户,该列总结了他们在 UserAchievement table 中列出的所有成就所获得的总分。
但显然我还没有完全了解注释的工作原理。当我尝试时:
users = User.objects.annotate(points=Sum('userachievement__achievement__points'))
for u in users:
print(u.email, u.points)
它崩溃了:
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/Users/dylan/.local/share/virtualenvs/server-E23dvZwD/lib/python3.7/site-packages/django/db/models/query.py", line 274, in __iter__
self._fetch_all()
File "/Users/dylan/.local/share/virtualenvs/server-E23dvZwD/lib/python3.7/site-packages/django/db/models/query.py", line 1242, in _fetch_all
self._result_cache = list(self._iterable_class(self))
File "/Users/dylan/.local/share/virtualenvs/server-E23dvZwD/lib/python3.7/site-packages/django/db/models/query.py", line 78, in __iter__
setattr(obj, attr_name, row[col_pos])
AttributeError: can't set attribute
您可以使用 ManyToManyField 从 User
到 Achievement
,使用 UserAchievement
作为直通 table 来简化您的查询
class User(AbstractUser):
email = models.EmailField(_('email address'), unique=True)
achievements = models.ManyToManyField('Achievement', through='UserAchievement')
...
这可以像这样用于注释
User.objects.annotate(points=Sum('achievements__points'))
如果你有一个用户实例
user.achievements.all()
至于错误,我相信您的用户模型上有一个名为 points
的 属性
我有三个模型,User、Achievement 和 UserAchievement:
class User(AbstractUser):
email = models.EmailField(_('email address'), unique=True)
...
class Achievement(models.Model):
name = models.CharField(max_length=64)
points = models.PositiveIntegerField(default=1)
class UserAchievement(models.Model):
# Use a lazy reference to avoid circular import issues
user = models.ForeignKey('users.User', on_delete=models.CASCADE)
achievement = models.ForeignKey(Achievement, on_delete=models.CASCADE)
我想用一个 'points' 列来注释用户,该列总结了他们在 UserAchievement table 中列出的所有成就所获得的总分。
但显然我还没有完全了解注释的工作原理。当我尝试时:
users = User.objects.annotate(points=Sum('userachievement__achievement__points'))
for u in users:
print(u.email, u.points)
它崩溃了:
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/Users/dylan/.local/share/virtualenvs/server-E23dvZwD/lib/python3.7/site-packages/django/db/models/query.py", line 274, in __iter__
self._fetch_all()
File "/Users/dylan/.local/share/virtualenvs/server-E23dvZwD/lib/python3.7/site-packages/django/db/models/query.py", line 1242, in _fetch_all
self._result_cache = list(self._iterable_class(self))
File "/Users/dylan/.local/share/virtualenvs/server-E23dvZwD/lib/python3.7/site-packages/django/db/models/query.py", line 78, in __iter__
setattr(obj, attr_name, row[col_pos])
AttributeError: can't set attribute
您可以使用 ManyToManyField 从 User
到 Achievement
,使用 UserAchievement
作为直通 table 来简化您的查询
class User(AbstractUser):
email = models.EmailField(_('email address'), unique=True)
achievements = models.ManyToManyField('Achievement', through='UserAchievement')
...
这可以像这样用于注释
User.objects.annotate(points=Sum('achievements__points'))
如果你有一个用户实例
user.achievements.all()
至于错误,我相信您的用户模型上有一个名为 points
的 属性