在 gremlin 中加入查询,将结果分组为一对多关系
Join query in gremlin, group results in a one to many relationship
我必须输入顶点国家和机场的类型,每个国家都有一个到多个机场的边,标签为 "hasAirport"
我正在尝试一个连接查询,它将 return 国家与他们拥有的机场分组。
g.V().hasLabel("Country").as("country").out('hasAirport').as("airport").select("country", "airport").by(__.unfold().valueMap(true).fold()).toList()
如果我的图表中只有一个国家(例如美国)和两个机场,则查询结果如下所示。
[ {
"country": [
{
"name": "United States",
"code": "USA", "label": "Country",
"id": 1565,
}
],
"airport": [
{
"id": 1234,
"label": "Airport",
"name": "San Francisco International Airport", "code": "SFO"
}
] }, {
"country": [
{
"name": "United States",
"code": "USA", "label": "Country",
"id": 1565,
}
],
"airport": [
{
"id": 2345,
"label": "Airport",
"name": "Austin Bergstrom International Airport", "code": "AUS"
}
] } ]
有没有办法像下面这样在一个数组中合并多个机场
[
{
"country": [
{
"name": "United States",
"code": "USA",
"label": "Country",
"id": 1565,
}
],
"airport": [
{
"id": 1234,
"label": "Airport",
"name": "San Francisco International Airport",
"code": "SFO"
},
{
"id": 2345,
"label": "Airport",
"name": "Austin Bergstrom International Airport",
"code": "AUS"
}
]
}
]
您需要使用project
:
g.V().hasLabel("Country")
.project("country","airport")
.by(valueMap(true))
.by(out('hasAirport').valueMap(true).fold())
我必须输入顶点国家和机场的类型,每个国家都有一个到多个机场的边,标签为 "hasAirport"
我正在尝试一个连接查询,它将 return 国家与他们拥有的机场分组。
g.V().hasLabel("Country").as("country").out('hasAirport').as("airport").select("country", "airport").by(__.unfold().valueMap(true).fold()).toList()
如果我的图表中只有一个国家(例如美国)和两个机场,则查询结果如下所示。
[ {
"country": [
{
"name": "United States",
"code": "USA", "label": "Country",
"id": 1565,
}
],
"airport": [
{
"id": 1234,
"label": "Airport",
"name": "San Francisco International Airport", "code": "SFO"
}
] }, {
"country": [
{
"name": "United States",
"code": "USA", "label": "Country",
"id": 1565,
}
],
"airport": [
{
"id": 2345,
"label": "Airport",
"name": "Austin Bergstrom International Airport", "code": "AUS"
}
] } ]
有没有办法像下面这样在一个数组中合并多个机场
[
{
"country": [
{
"name": "United States",
"code": "USA",
"label": "Country",
"id": 1565,
}
],
"airport": [
{
"id": 1234,
"label": "Airport",
"name": "San Francisco International Airport",
"code": "SFO"
},
{
"id": 2345,
"label": "Airport",
"name": "Austin Bergstrom International Airport",
"code": "AUS"
}
]
}
]
您需要使用project
:
g.V().hasLabel("Country")
.project("country","airport")
.by(valueMap(true))
.by(out('hasAirport').valueMap(true).fold())