在 Python 的剪刀石头布游戏中创建 while 循环

Question

我对编程很陌生，正在寻找有关房主分配的帮助。赋值如下：

使用默认 python 函数编写一个程序，让用户可以在计算机上玩剪刀石头布游戏。该程序应按如下方式工作：

程序开始时，会生成一个1到3范围内的随机数。如果数字是 1，则计算机选择了岩石。如果数字是 2，那么计算机选择了纸，如果数字是 3，那么计算机选择了剪刀。
用户在键盘上输入"rock"、"paper"或"scissors"。
显示电脑的选择
根据以下规则选出获胜者。

当计算机或用户赢得单局时，游戏应结束，并在结果为平局时继续。非常感谢任何帮助。

 from random import randint

 #create a list of play options
 t = ["Rock", "Paper", "Scissors"]

 #assign a random play to the computer
 computer = t[randint(1,3)]

 #set player to False
 player = False

 while player == False:
 #set player to True
     player = input("Rock, Paper, Scissors?")
     if player == computer:
         print("Tie!")
     elif player == "Rock":
         if computer == "Paper":
             print("You lose!", computer, "covers", player)
         else:
             print("You win!", player, "smashes", computer)
     elif player == "Paper":
         if computer == "Scissors":
             print("You lose!", computer, "cut", player)
         else:
             print("You win!", player, "covers", computer)
     elif player == "Scissors":
         if computer == "Rock":
             print("You lose...", computer, "smashes", player)
         else:
             print("You win!", player, "cut", computer)
     else:
         print("That's not a valid play. Check your spelling!")
      #player was set to True, but we want it to be False so the loop continues
     player = False
     computer = t[randint(1,3)]

Answer 1

第一个问题是你选错了电脑。 Python 中的列表作为绝大多数编程语言中的数组，从 0 开始。在您的情况下，您生成的数字范围在 1 到 3 之间，即它永远不会获得 [=11= 的第一个元素] 并且当数字为 3 时将失败，因为列表以 2 结尾。

对于该部分，您可以生成一个从 0 到 2 的数字，或者使用 random 模块中的 choice() 方法。请注意，您需要先导入它。

此外，我宁愿将 while True 与一些 break 一起使用，而不是老式的状态变量。这是您的代码的工作版本，进行了相同的重构：

from random import choice

#create a list of play options
t = ["Rock", "Paper", "Scissors"]

while True:
    computer = choice(t)

    player = input("Rock, Paper, Scissors?")

    if player == computer:
        print("Tie!")
    elif player == "Rock":
        if computer == "Paper":
            print("You lose!", computer, "covers", player)
        else:
            print("You win!", player, "smashes", computer)
        break
    elif player == "Paper":
        if computer == "Scissors":
            print("You lose!", computer, "cut", player)
        else:
            print("You win!", player, "covers", computer)
        break
    elif player == "Scissors":
        if computer == "Rock":
            print("You lose...", computer, "smashes", player)
        else:
            print("You win!", player, "cut", computer)
        break
    else:
        print("That's not a valid play. Check your spelling!")

在 Python 的剪刀石头布游戏中创建 while 循环

Creating a while loop in Rock Paper Scissors game for Python

python

python-3.7