为什么我无法验证 Swift 中登录按钮中的文本字段

Question

我已将委托委托给我的所有文本字段，但我无法验证文本字段最初是否为空..如果我只是将光标放在文本字段中，但没有任何文本，那么我可以检查，然后它说请输入电话号码为什么？

如果我没有将光标放在文本字段中，则访问直接转到其他部分，即使所有文本字段都是空的这是我的代码，请在代码中帮助我。

func textFieldDidBeginEditing(_ textField: UITextField) {
    textField.text = ""
}
//MARK:- ButtonActions
@IBAction func loginButton(_ sender: Any) {

     if(userIdTextFielf.text?.isEmpty)!{
        AlertFun.ShowAlert(title: "", message: "Please enter PhoneNumber", in: self)
    }
    else if(passwordTextField.text?.isEmpty)!{
        AlertFun.ShowAlert(title: "", message: "Please enter Password", in: self)
    }
    else if(passwordTextField.text?.isEmpty)! && (userIdTextFielf.text?.isEmpty)! {
        AlertFun.ShowAlert(title: "", message: "Please enter PhoneNumber & Password", in: self)
    }
    else{
        logInService()
    }
    }

这是我的登录服务：

 //MARK:- Service part
func logInService(){

    let parameters = ["username":Int(userIdTextFielf.text ?? "") as Any,
                      "imei_number":"test2012@gmail.com",
                      "password":passwordTextField.text as Any,
                      "name":"name"]

    let url = URL(string: "https://dev.com/webservices/login")
    var req =  URLRequest(url: url!)
    req.httpMethod = "POST"
    req.addValue("application/json", forHTTPHeaderField: "Contet-Type")
    req.addValue("application/json", forHTTPHeaderField: "Accept")

    guard let httpBody = try? JSONSerialization.data(withJSONObject: parameters as Any, options: .prettyPrinted) else {return}
    req.httpBody = httpBody
    let session = URLSession.shared
    session.dataTask(with: req, completionHandler: {(data, response, error) in
        if response != nil {
            // print(response)
        }
        if let data = data {
            do{

                let json = try JSONSerialization.jsonObject(with: data, options: .mutableContainers) as! [String: Any]
                print("the json of loginnnnnn \(json)")
                var loginStatus = json["status"] as? String
                DispatchQueue.main.async {
                    if loginStatus == "Failed"
                    {
                       AlertFun.ShowAlert(title: "", message: "Invalid creadintials", in: self)
                    }
                    else{
                        self.Uid = json["id"] as? String
                        let emailL = json["user_email"] as? String
                        print("login uid \(self.Uid)")

                        KeychainWrapper.standard.set(emailL ?? "", forKey: "user_email")
                        let saveUserId: Bool = KeychainWrapper.standard.set(self.Uid!, forKey: "Uid")

                        let mainStoryBoard = UIStoryboard(name: "Main", bundle: nil)
                        let navigationController = mainStoryBoard.instantiateViewController(withIdentifier: "HomeNavigation")
                        let appDelagate = UIApplication.shared.delegate
                        appDelagate?.window??.rootViewController = navigationController
                    }
                }
            }catch{
                print("error")
            }
        }
    }).resume()
}

如果我点击没有电话号码和密码的登录按钮，它总是显示 Invalid creadintials

请帮我写代码。

Answer 1

使用 isEmpty 而不是等于 ""

Answer 2

您可以尝试这个或最重要的解决方案

    if userIdTextFielf.text?.isEmptyOrWhitespace() ?? true
    {
         AlertFun.ShowAlert(title: "", message: "Please enter PhoneNumber", in: self)
        return
    }
    else if passwordTextField.text?.isEmptyOrWhitespace() ?? true
    {
         AlertFun.ShowAlert(title: "", message: "Please enter Password", in: self)
    return
    }

extension String {
func isEmptyOrWhitespace() -> Bool {
    if(self.isEmpty) {
        return true
    }
    return (self.trimmingCharacters(in: NSCharacterSet.whitespaces) == "")
}

Answer 3

您似乎在文本字段的 text 属性中放置了一些占位符字符串。通常我们不会那样做。将占位符字符串放在文本字段的 placeholder 属性中，它会准确地执行您想要的操作，即如果为空则显示占位符文本，否则显示用户输入的内容。然后你就不需要 textFieldDidBeginEditing 实现，你的简单 isEmpty 检查就可以了。

如果您想使用 text 属性执行您自己的手动占位符过程，那么您必须更改验证逻辑，同时检查 isEmpty 和它不是等于您的占位符文本。

例如，您可以使用实用程序方法来确定用户实际输入的内容（即，如果它等于默认文本字符串，则 return 零长度字符串）：

@IBAction func didTapLogin(_ sender: Any) {
    let userid = actualInput(for: useridTextField, defaultText: "Enter userid")
    let password = actualInput(for: passwordTextField, defaultText: "Enter password")

    switch (userid.isEmpty, password.isEmpty) {
    case (true, true):
        AlertFun.showAlert(title: "", message: "Please enter PhoneNumber & Password", in: self)

    case (true, _):
        AlertFun.showAlert(title: "", message: "Please enter PhoneNumber", in: self)

    case (_, true):
        AlertFun.showAlert(title: "", message: "Please enter Password", in: self)

    default:
        logInService()
    }
}

func actualInput(for textField: UITextField, defaultText: String) -> String {
    let text = textField.text ?? ""
    if text == defaultText {
        return ""
    } else {
        return text.trimmingCharacters(in: .whitespacesAndNewlines)
    }
}

就个人而言，即使您在 text 技巧中使用自定义占位符，我仍可能会将占位符字符串存储在 placeholder 属性中以保存它。我也可以将其移动到 UITextField:

的扩展

extension UITextField {
    var userInput: String? { text == placeholder ? "" : text }
}

那么你可以这样做：

class ViewController: UIViewController {

    @IBOutlet weak var imageView: UIImageView!

    @IBOutlet weak var useridTextField: UITextField!
    @IBOutlet weak var passwordTextField: UITextField!

    override func viewDidLoad() {
        super.viewDidLoad()

        useridTextField.placeholder = "Please enter userid"
        passwordTextField.placeholder = "Please enter password"

        useridTextField.text = useridTextField.placeholder
        passwordTextField.text = passwordTextField.placeholder
    }

    @IBAction func didTapLogin(_ sender: Any) {
        let userid = useridTextField.userInput ?? ""
        let password = passwordTextField.userInput ?? ""

        switch (userid.isEmpty, password.isEmpty) {
        case (true, true):
            AlertFun.showAlert(title: "", message: "Please enter PhoneNumber & Password", in: self)

        case (true, _):
            AlertFun.showAlert(title: "", message: "Please enter PhoneNumber", in: self)

        case (_, true):
            AlertFun.showAlert(title: "", message: "Please enter Password", in: self)

        default:
            logInService()
        }
    }

    func logInService() { ... }
}

extension ViewController: UITextFieldDelegate {
    func textFieldDidBeginEditing(_ textField: UITextField) {
        if textField.text == textField.placeholder {
            textField.text = ""
        }
    }

    func textFieldDidEndEditing(_ textField: UITextField, reason: UITextField.DidEndEditingReason) {
        if textField.text?.isEmpty ?? true {
            textField.text = textField.placeholder
        }
    }
}

这样，您就可以避免在代码中散布字符串文字，即使用户点击字段（您删除文本的地方），他们现在也可以看到占位符字符串，因此他们知道要输入什么，等等。

为什么我无法验证 Swift 中登录按钮中的文本字段

Why I'm unable to validate textFields in login Button in Swift

if-statement

uitextfield

ios

swift