有没有一种简单的方法可以制作类似的 1 线计算器？

Question

作为初学者，我尝试使用 Python 来制作单行计算器...然后我来到了这里。我将用户输入转换为列表，然后使用列表元素来获取结果。例如，如果乘法，我将符号前的元素组合起来，然后将符号后的元素组合起来 them.Then 将它们相乘。

question = list(input("Enter Your Question: "))
def convert(list): 
    s = [str(i) for i in list] 
    combined = int("".join(s)) 
    list = combined
    return(combined)
multiply = "*"
add = "+"
substract = "-"
divide = "/"
if multiply in question:
    for multiply in question:
        position1 = question.index("*")
        before_num = question[0: int(position1)]
        aft = len(question)
        after_num = question[int(position1) + 1: int(aft)]
        num_before = convert(before_num)
        num_after = convert(after_num)
        print(int(num_before) * int(num_after))
        break
elif add in question:
    for add in question:
        position1 = question.index("+")
        before_num = question[0: int(position1)]
        aft = len(question)
        after_num = question[int(position1) + 1: int(aft)]
        num_before = convert(before_num)
        num_after = convert(after_num)
        print(int(num_before) + int(num_after))
        break
elif substract in question:
    for substract in question:
        position1 = question.index("-")
        before_num = question[0: int(position1)]
        aft = len(question)
        after_num = question[int(position1) + 1: int(aft)]
        num_before = convert(before_num)
        num_after = convert(after_num)
        print(int(num_before) - int(num_after))
        break
elif divide in question:
    for divide in question:
        position1 = question.index("/")
        before_num = question[0: int(position1)]
        aft = len(question)
        after_num = question[int(position1) + 1: int(aft)]
        num_before = convert(before_num)
        num_after = convert(after_num)
        print(int(num_before) / int(num_after))
        break
else:
    print("Check Your Question Again")
end_program_ans = input("Press Enter to continue")

这很完美，但有没有更简单的方法。

Answer 1

read_data = input("Enter Your Question: ")
if "*" in read_data:
    data1,data2 = read_data.split("*")
    print(float(data1)*float(data2))
elif "+" in read_data:
    data1,data2 = read_data.split("+")
    print(float(data1)+float(data2))
elif "-" in read_data:
    data1,data2 = read_data.split("-")
    print(float(data1)-float(data2))
elif "/" in read_data:
    data1,data2 = read_data.split("/")
    print(float(data1)/float(data2))
else:
    print("Please Enter Proper data")

有没有一种简单的方法可以制作类似的 1 线计算器？

Is there a simple way to make similar 1-Line Calculator?

python

calculator