如何在 1 行中排列金额、借方、贷方和余额

Question

我想将我的查询排列成单行（每个 cdvno、金额、借方、贷方和余额一行）但是我不能安排他们。成1单排

示例代码

select a.cdvno,b.Amount, a.debit, a.credit, a.credit + a.debit - coalesce(b.amount,0) as balance
from (
    select cdvno, debit, sum(credit) credit, trantype
    from cdvdtl  
    where debit = 0
    group by cdvno, debit, trantype
    union all
    select cdvno, sum(debit) debit, credit, trantype
    from cdvdtl  
    where credit = 0
    group by cdvno, credit, trantype
) a
left join cdvhdr b
    on b.cdvno = a.cdvno
    and b.trantype = a.trantype
where  a.credit + a.debit - coalesce(b.amount,0) <> 0
order by a.cdvno

结果

cdvno               Amount      debit     credit    balance
000-2016-01000004   25137.50    25326.16    0.00    188.66
000-2016-01000004   25137.50    0.00    25326.16    188.66
000-2016-01000005   15849.90    0.00    16010.00    160.10
000-2016-01000005   15849.90    16010.00    0.00    160.10
000-2016-01000007   217938.73   0.00    220006.50   2067.77
000-2016-01000007   217938.73   220006.50   0.00    2067.77

我尝试了(sum)amount 但它不起作用。如果可能的话，我希望结果是这样的

cdvno             Amount        debit       credit      balance
000-2016-01000004   25137.5     25326.16    25326.16    188.66
000-2016-01000005   15849.9     16010       16010       160.1
000-2016-01000007   217938.73   220006.5    220006.5    2067.77

非常感谢，我知道这对你们来说很简单，但对我来说我被困在这里了:D newbee

Answer 1

您可以忽略 union（这会导致为借记和 credit 创建单独的条目）并改用 select case。

select a.cdvno,b.Amount
    , a.debit
    , a.credit
    , coalesce(b.amount,0) - coalesce(a.debit, a.credit) as balance
from (
    select cdvno
        , sum(case when credit = 0 then debit else 0 end) as debit
        , sum(case when debit = 0 then credit else 0 end) credit
        , trantype
    from cdvdtl    
    group by cdvno, trantype    
) a 
left join cdvhdr b
     on b.cdvno = a.cdvno and b.trantype = a.trantype
where  a.credit + a.debit - coalesce(b.amount,0) <> 0
    order by a.`cdvno`

Answer 2

我认为你想要聚合条件聚合。这对我来说很有意义：

select d.cdvno,
       sum(case when d.credit = 0 then d.debit end) as debit,
       sum(case when d.debit = 0 then d.credit end) as credit,
       (h.amount +
        sum(case when d.debit = 0 then d.credit end) -
        sum(case when d.credit = 0 then d.debit end)
       ) as balance
from cdvdtl d join
     cdvhdr h
     on h.cdvno = d.cdvno and h.trantype = d.trantype
group by d.cdvno, h.amount
order by d.cdvno;

注意 table 别名的使用。这些不是任意字母，而是 table 名称的缩写。

如何在 1 行中排列金额、借方、贷方和余额

How to arrange the Amount,Debit,Credit and balance in 1 row

sql

sql-server-2008