PLS-00049 错误的绑定变量 'NEW.NUM_CUENTA'

Question

我正在 Oracle 中为一个名为 empleado 的视图执行此触发器，但出现此错误

18/40 PLS-00049 bad bind variable 'NEW.NUM_CUENTA'

谁能帮我看看我做错了什么

触发器是：

create or replace trigger t_dml_empleado
instead of insert or delete on empleado
declare

begin 
    case 
        when inserting then 
            if (SUBSTR(rfc, 1,1) BETWEEN 'A' and 'M') then 
                insert into empleado_2 (empleado_id, nombre, ap_paterno, ap_materno, rfc, email, jefe_id)
                values(:new.empleado_id, :new.nombre, :new.ap_paterno, :new.ap_materno, 
                        :new.rfc, :new.email, :new.jefe_id);
            elsif (SUBSTR(rfc, 1,1) BETWEEN 'N' and 'Z')    then 
                insert into empleado_3 (empleado_id, nombre, ap_paterno, ap_materno, rfc, email, jefe_id)
                values (:new.empleado_id, :new.nombre, :new.ap_paterno, :new.ap_materno,
                        :new.rfc, :new.email, :new.jefe_id);
            else
                raise_application_error(20001,'Valor incorrecto para RFC: '|| :new.rfc);
            end if;
            insert into empleado_1(empleado_id, foto, num_cuenta)
            values (:new.empleado_id, :new.foto,:new.num_cuenta);

        when deleting then 
            if (SUBSTR(rfc, 1,1) BETWEEN 'A' and 'M')  then 
                delete from empleado_2 where empleado_id =:old.empleado_id;
            elsif (SUBSTR(rfc, 1,1) BETWEEN 'N' and 'Z')    then
                delete from empleado_3 where empleado_id = :old.empleado_id;            
            else
                raise_application_error(20001,'Valor incorrecto para RFC: '|| :new.rfc);
            end if;
            delete from empleado_1 where empleado_id = :old.empleado_id;
    end case;
end;

第二行解释empleado是一个视图，在一个PDB中：

create or replace view empleado as
    select q1.empleado_id, q1.nombre, q1.ap_paterno, q1.ap_materno, q1.rfc,q1.email, q1.jefe_id, foto
    from (
            select empleado_id, nombre, ap_paterno, ap_materno, rfc,email, jefe_id 
            from empleado_2
            union
            select empleado_id, nombre, ap_paterno, ap_materno, rfc,email, jefe_id 
            from empleado_3
         ) q1,(select empleado_id, foto, num_cuenta 
                   from empleado_1) q2
            where q1.empleado_id=q2.empleado_id;

即来自三个表empleado_3，empleado_1在一个PDB中，empleado_2在另一个PDB中。该视图正在连接远程表。

我创建了同义词，所以问题不存在。这些表格是：


CREATE TABLE F_AMG_EMPLEADO_1
(
    EMPLEADO_ID          NUMERIC(10,0) NOT NULL ,
    FOTO                 BLOB NOT NULL ,
    NUM_CUENTA           VARCHAR2(18) NOT NULL 
);
CREATE TABLE F_AMG_EMPLEADO_3
(
    EMPLEADO_ID          NUMERIC(10,0) NOT NULL ,
    NOMBRE               VARCHAR2(40) NOT NULL ,
    AP_PATERNO           VARCHAR2(40) NOT NULL ,
    AP_MATERNO           VARCHAR2(40) NOT NULL ,
    RFC                  VARCHAR2(13) NOT NULL ,
    EMAIL                VARCHAR2(40) NOT NULL ,
    JEFE_ID              NUMERIC(10,0) NULL 
);

Answer 1

这是您的视图投影：

select q1.empleado_id, q1.nombre, q1.ap_paterno, q1.ap_materno, q1.rfc,q1.email, q1.jefe_id, foto

这些是仅有的列 您可以在基于该视图构建的触发器t_dml_empleado 中引用。如您所见，视图的投影中没有提及 num_cuenta 。因此，您不能在触发器中引用 :new.num_cuenta。

至于解决方案，要么更改触发器，要么将 num_cuenta 添加到在视图定义中选择的列。

Answer 2

在视图 empleado 中，您没有名为 num_cuenta 的列。您必须像我在 DEMO 中所做的那样在视图中 select 它。

下一个错误是在 WHEN INSERTING 和 WHEN DELETING 的触发器中使用 case when。我已经用 if then elsif

改变了它

接下来的问题是在 SUBSTR 函数中使用 rfc。您必须像我在我的演示中那样引用 :new 或 :old 值。这是起作用的触发器：

create or replace trigger t_dml_empleado
instead of insert or delete on empleado
declare

begin 
    if inserting then 
            if (SUBSTR(:new.rfc, 1,1)) BETWEEN 'A' and 'M' then
               insert into empleado_2 (empleado_id, nombre, ap_paterno, ap_materno, rfc, email, jefe_id)
                values(:new.empleado_id, :new.nombre, :new.ap_paterno, :new.ap_materno, 
                        :new.rfc, :new.email, :new.jefe_id);
            elsif (SUBSTR(:new.rfc, 1,1) BETWEEN 'N' and 'Z') then 
                insert into empleado_3 (empleado_id, nombre, ap_paterno, ap_materno, rfc, email, jefe_id)
                values (:new.empleado_id, :new.nombre, :new.ap_paterno, :new.ap_materno,
                        :new.rfc, :new.email, :new.jefe_id);
             else
                raise_application_error(20001,'Valor incorrecto para RFC: '|| :new.rfc);
            end if;
    elsif deleting then 
            if (SUBSTR(:old.rfc, 1,1)) BETWEEN 'A' and 'M'  then 
                delete from empleado_2 where empleado_id =:old.empleado_id;
            elsif (SUBSTR(:new.rfc, 1,1) BETWEEN 'N' and 'Z')    then
                delete from empleado_3 where empleado_id = :old.empleado_id;            
            else
                raise_application_error(20001,'Valor incorrecto para RFC: '|| :new.rfc);
            end if;
            delete from empleado_1 where empleado_id = :old.empleado_id;
    end if;
end;
/

这里是DEMO。我希望这会帮助您解决问题。干杯！

PLS-00049 错误的绑定变量 'NEW.NUM_CUENTA'

PLS-00049 bad bind variable 'NEW.NUM_CUENTA'

sql

plsql

oracle18c