在 PostgreSQL 中直到当前日期的每月工作日

Question

我想在 PostgreSQL 中获取到当前日期为止的一个月的工作日数。

例如，本月到今天，工作日为17。我如何从下面的查询或一般解决方案中获得这个？

SELECT 
    TO_CHAR(i, 'YYYY-MM') as year_month,
    i::date as date,
    EXTRACT(DOW FROM i) as number_weekday,
    CASE WHEN EXTRACT(DOW FROM i) IN ('1', '2', '3', '4', '5') 
                  AND i NOT IN ('2018-01-01', '2018-03-30', '2018-04-02', '2018-05-01', '2018-05-10', '2018-05-21', '2018-10-03', '2018-12-25', '2018-12-26',
                                    '2019-01-01', '2019-04-19', '2019-04-22', '2019-05-01', '2019-05-30', '2019-06-10', '2019-10-03', '2019-12-25', '2019-12-26',
                                    '2020-01-01', '2020-04-10', '2020-04-13', '2020-05-01', '2020-05-21', '2020-06-01', '2020-10-03', '2020-12-25', '2020-12-26',
                                    '2021-01-01', '2021-04-02', '2021-04-05', '2021-05-01', '2021-05-13', '2021-05-24', '2021-10-03', '2021-12-25', '2021-12-26')
              THEN 'Working Day' ELSE 'Non Working Day' END as day_type

    FROM 
        generate_series('2017-12-31', '2022-01-01', '1 day'::interval) i
   WHERE 
    i::date < CURRENT_DATE
    ORDER BY 
        date DESC

Answer 1

I want to get the number of working days of the month until current date

刚刚：

select sum( (extract(dow from d) between 1 and 5)::int ) month_working_days_till_date
from generate_series(date_trunc('month', now()) , now(), interval '1 day') x(d)

generate_seires() 生成从月初到今天的一系列日期。然后我们做一个只计算工作日的条件sum()。请注意，这没有考虑潜在的假期（为此，您需要一个日历 table）。

Demo on DB Fiddle:

| month_working_days_till_date |
| ---------------------------: |
|                           17 |

Answer 2

作为一个通用的解决方案，我认为最好的是GMB的答案。

如果你想从你提供的查询中做同样的事情，你可以这样做：

WITH days AS
(
    SELECT 
    TO_CHAR(i, 'YYYY-MM') as year_month,
    i::date as date,
    EXTRACT(DOW FROM i) as number_weekday,
    CASE WHEN EXTRACT(DOW FROM i) IN ('1', '2', '3', '4', '5') 
                  AND i NOT IN ('2018-01-01', '2018-03-30', '2018-04-02', '2018-05-01', '2018-05-10', '2018-05-21', '2018-10-03', '2018-12-25', '2018-12-26',
                                    '2019-01-01', '2019-04-19', '2019-04-22', '2019-05-01', '2019-05-30', '2019-06-10', '2019-10-03', '2019-12-25', '2019-12-26',
                                    '2020-01-01', '2020-04-10', '2020-04-13', '2020-05-01', '2020-05-21', '2020-06-01', '2020-10-03', '2020-12-25', '2020-12-26',
                                    '2021-01-01', '2021-04-02', '2021-04-05', '2021-05-01', '2021-05-13', '2021-05-24', '2021-10-03', '2021-12-25', '2021-12-26')
              THEN 'Working Day' ELSE 'Non Working Day' END as day_type

    FROM 
        generate_series('2017-12-31', '2022-01-01', '1 day'::interval) i
   WHERE 
    i::date <= CURRENT_DATE
    ORDER BY 
        date DESC
)
SELECT year_month, SUM((day_type = 'Working Day'):: int) 
FROM days
WHERE 
     date >= date_trunc('month', now())
GROUP BY year_month;

DEMO HERE

在 PostgreSQL 中直到当前日期的每月工作日

Working days of month until current date in PostgreSQL

sql

postgresql

datetime

date

recursive-query