foreach 未执行 - 仅显示第一个变量输入

Question

我试图弄清楚为什么我的 foreach 循环没有提供一个以上的变量（第一个变量）- 我正在尝试创建一个电子商务网站，这是我的购物车的保存功能。两个 sql 语句都是正确的并且进入了我的数据库。

有两个 table - 一个发票 table 和另一个 table 我将显示订购的产品。我正在使用重置功能来获取我在另一个功能中上传的图像的 ID。

大家有什么想法吗？

public static function submit()
{        
    $nOrderNum = date("Y-m-d").mt_rand();
    $orderDate = date("Y-m-d h:m:s");
    $firstname = $_POST["firstname"];
    $lastname = $_POST["lastname"];
    $email = $_POST["email"];
    $phone = $_POST["phone"];
    $address = $_POST["address"];
    $imgID = AllMerch::getImgs();
    $orderToggle = 0;
    $value = reset($imgID);

    $con = Db::connect();

    mysqli_query($con,"
    INSERT INTO invoice 
    (
        nOrderNum, 
        strOrderDate, 
        strName, 
        strLast, 
        strEmail, 
        nPhone, 
        strAddress, 
        nPrice, 
        bOrderToggle
        ) VALUES (
            '".$nOrderNum."', 
            '".$orderDate."', 
            '".$firstname."', 
            '".$lastname."',
            '".$email."',
            '".$phone."',
            '".$address."',
            '".Cart::checkoutTotal()."',
            '".$orderToggle."'
            )");

        $invoiceID =  mysqli_insert_id($con);

    foreach($_SESSION["arrCart"] as $merch){        

    mysqli_query($con,"
        INSERT INTO merch_history 
        (
            nInvoiceID,
            nProductsID,
            nQty,
            nPrice, 
            nImgID
        ) VALUES (
            '".$invoiceID."',
            '".$merch["id"]."',
            '".$merch["currentQty"]."',
            '".$merch["price"]."',
            '".$value."'

        )");

        $sql = "UPDATE products SET nQty = nQty - '".$merch["currentQty"]."' WHERE id = '".$merch["id"]."'";

        $sql = "UPDATE images SET nInvoiceID = '".$invoiceID."' WHERE nSessionID = '".$_SESSION['id']."'";

        mysqli_query($con,$sql);

        $sql = "SELECT 
        merch_history.id, 
        merch_history.nInvoiceID, 
        merch_history.nProductsID, 
        merch_history.nQty, 
        merch_history.nPrice, 
        images.id AS imgID,
        images.strImage AS strImg
        FROM merch_history 
        LEFT JOIN images ON  images.id = merch_history.nImgID 
        ";

    $_SESSION['arrCart'] = array();
    return $invoiceID;
}
}

Answer 1

您的 return $invoiceID; 在 for 循环内，尝试在循环外删除它。

Answer 2

执行此操作，因为最后 2 个语句在循环中，如我所示将它们取出：

    foreach($_SESSION["arrCart"] as $merch){        

        mysqli_query($con,"
            INSERT INTO merch_history 
            (
                nInvoiceID,
                nProductsID,
                nQty,
                nPrice, 
                nImgID
            ) VALUES (
                '".$invoiceID."',
                '".$merch["id"]."',
                '".$merch["currentQty"]."',
                '".$merch["price"]."',
                '".$value."'

            )");

            $sql = "UPDATE products SET nQty = nQty - '".$merch["currentQty"]."' WHERE id = '".$merch["id"]."'";

            $sql = "UPDATE images SET nInvoiceID = '".$invoiceID."' WHERE nSessionID = '".$_SESSION['id']."'";

            mysqli_query($con,$sql);

            $sql = "SELECT 
            merch_history.id, 
            merch_history.nInvoiceID, 
            merch_history.nProductsID, 
            merch_history.nQty, 
            merch_history.nPrice, 
            images.id AS imgID,
            images.strImage AS strImg
            FROM merch_history 
            LEFT JOIN images ON  images.id = merch_history.nImgID 
            ";
    }


$_SESSION['arrCart'] = array();
return $invoiceID;

foreach 未执行 - 仅显示第一个变量输入

foreach not executing - only showing the first variable input

php

mysql

e-commerce