QueryDSL 按计算字段排序
QueryDSL Order by calculated field
在我们的应用程序中,我们使用 querydsl 来获取实体并将它们转换为表示对象。
此表示对象具有名为 active
的字段。这是由实体的某个日期是在今天之前(active = false)还是在今天之后(active = true)决定的。这样做一切顺利。问题是在尝试按该表达式 (QEntity.someDate > today
) 排序时。这使得休眠抛出这个错误:
org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: > near line 3, column 40 [select object.someField as someAlias, (object.someDate > ?1) as active, object as objectAlias
from com.example.Object object
order by object.someDate > ?1 asc]
我创建 OrderSpecifier
如下:
@Override
public OrderSpecifier<?> getOrderByClause(SortKey sortKey) {
BooleanExpression expression = getBooleanPath(); // This is the expression: (object.someDate > ?1)
if (sortKey.getSortOrder() == ESortOrder.ASCENDING) {
return new OrderSpecifier(Order.ASC, expression);
}
return new OrderSpecifier(Order.DESC, expression);
}
我也这样试过:
@Override
public OrderSpecifier<?> getOrderByClause(SortKey sortKey) {
BooleanExpression expression = getBooleanPath();
if (sortKey.getSortOrder() == ESortOrder.ASCENDING) {
return new CaseBuilder().when(expression.isFalse()).then(1).otherwise(2).asc();
}
return new CaseBuilder().when(expression.isTrue()).then(1).otherwise(2).desc();
}
这会导致类似的错误:
org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: > near line 3, column 40 [select object.someField as someAlias, (object.someDate > ?1) as active, object as objectAlias
from com.example.Object object
order by case when (object.someDate > ?1 = ?2) then ?3 else 2 end asc]
最后像这样:
@Override
public OrderSpecifier<?> getOrderByClause(SortKey sortKey) {
BooleanExpression expression = getBooleanPath();
if (sortKey.getSortOrder() == ESortOrder.ASCENDING) {
return new CaseBuilder().when(expression.eq(true)).then(1).otherwise(2).asc();
}
return new CaseBuilder().when(expression.eq(true)).then(1).otherwise(2).desc();
}
抛出与之前相同的错误
通过创建这样的 order 子句修复了它:
@Override
public OrderSpecifier<?> getOrderByClause(SortKey sortKey) {
BooleanPath path = getBooleanPath();
if (sortKey.getSortOrder() == ESortOrder.ASCENDING) {
return path.asc();
}
return path.desc();
}
private BooleanPath getBooleanPath() {
return Expressions.booleanPath(getFieldName());
}
其中字段名称是字符串的别名,在我们的例子中是 "active"
。
在我们的应用程序中,我们使用 querydsl 来获取实体并将它们转换为表示对象。
此表示对象具有名为 active
的字段。这是由实体的某个日期是在今天之前(active = false)还是在今天之后(active = true)决定的。这样做一切顺利。问题是在尝试按该表达式 (QEntity.someDate > today
) 排序时。这使得休眠抛出这个错误:
org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: > near line 3, column 40 [select object.someField as someAlias, (object.someDate > ?1) as active, object as objectAlias
from com.example.Object object
order by object.someDate > ?1 asc]
我创建 OrderSpecifier
如下:
@Override
public OrderSpecifier<?> getOrderByClause(SortKey sortKey) {
BooleanExpression expression = getBooleanPath(); // This is the expression: (object.someDate > ?1)
if (sortKey.getSortOrder() == ESortOrder.ASCENDING) {
return new OrderSpecifier(Order.ASC, expression);
}
return new OrderSpecifier(Order.DESC, expression);
}
我也这样试过:
@Override
public OrderSpecifier<?> getOrderByClause(SortKey sortKey) {
BooleanExpression expression = getBooleanPath();
if (sortKey.getSortOrder() == ESortOrder.ASCENDING) {
return new CaseBuilder().when(expression.isFalse()).then(1).otherwise(2).asc();
}
return new CaseBuilder().when(expression.isTrue()).then(1).otherwise(2).desc();
}
这会导致类似的错误:
org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected AST node: > near line 3, column 40 [select object.someField as someAlias, (object.someDate > ?1) as active, object as objectAlias
from com.example.Object object
order by case when (object.someDate > ?1 = ?2) then ?3 else 2 end asc]
最后像这样:
@Override
public OrderSpecifier<?> getOrderByClause(SortKey sortKey) {
BooleanExpression expression = getBooleanPath();
if (sortKey.getSortOrder() == ESortOrder.ASCENDING) {
return new CaseBuilder().when(expression.eq(true)).then(1).otherwise(2).asc();
}
return new CaseBuilder().when(expression.eq(true)).then(1).otherwise(2).desc();
}
抛出与之前相同的错误
通过创建这样的 order 子句修复了它:
@Override
public OrderSpecifier<?> getOrderByClause(SortKey sortKey) {
BooleanPath path = getBooleanPath();
if (sortKey.getSortOrder() == ESortOrder.ASCENDING) {
return path.asc();
}
return path.desc();
}
private BooleanPath getBooleanPath() {
return Expressions.booleanPath(getFieldName());
}
其中字段名称是字符串的别名,在我们的例子中是 "active"
。