JPA/Hibernate:如何在同一会话中为具有@Id 注释的字段保留重复值?
JPA/Hibernate: How to persist duplicate values in same session for field having @Id annotation?
客户说子 Table 中不需要主键。所以 Child table 有两列 "ID" 和 "Value",其中 ID 可以重复。
当我删除@Id 然后休眠说 "No identifier specified for entity"
当我在代码中保留@Id 时,hibernate 说 "javax.persistence.EntityExistsException: a different object with the same identifier value was already associated with the session";在坚持的同时
关键是我需要保留@Id,但如何使用@Id 注释在一个会话中保留两个相同的ID。
代码如下:
主要实体:
public class CustomerAgreement implements Serializable {
@OneToMany(mappedBy = "customerAgreement", orphanRemoval = true, fetch = FetchType.LAZY, cascade = {CascadeType.PERSIST})
private List<CustomerAgreementComputerAttachments> autoAttachComputersFromOrganizations;
组合实体:
public class CustomerAgreementComputerAttachments implements Serializable{
private static final long serialVersionUID = 1L;
@Id
@ManyToOne
@JoinColumn(name = "ID")
private CustomerAgreement customerAgreement;
主程序:
public static List<CustomerAgreement> create() {
List<CustomerAgreement> li = new ArrayList<CustomerAgreement>();
CustomerAgreement cAgreement = new CustomerAgreement();
cAgreement.setId(2222l);
cAgreement.setName("Tillu");;
cAgreement.setCustomerId("140");
List<CustomerAgreementComputerAttachments> catl = new ArrayList<>();
CustomerAgreementComputerAttachments catt = new CustomerAgreementComputerAttachments();
catt.setAttachmentValue("TEST");
catt.setCustomerAgreement(cAgreement);
CustomerAgreementComputerAttachments tatt = new CustomerAgreementComputerAttachments();
tatt.setAttachmentValue("TESTy");
tatt.setCustomerAgreement(cAgreement);
catl.add(catt);
catl.add(tatt);
cAgreement.setAutoAttachComputersFromOrganizations(catl);
li.add(cAgreement);
return li;
}
public static void main(String[] args) {
EntityManagerFactory emf = Persistence.createEntityManagerFactory("IntegratorMasterdataPU");
em = emf.createEntityManager();
em.getTransaction().begin();
for(CustomerAgreement ca: create()) {
em.persist(ca);
}
em.getTransaction().commit();
}
实体必须可由唯一键识别。这不需要对应于任何数据库主键,但必须有一个或多个可用于标识实体的唯一列。
如果这不可能,那么您需要将 CustomerAgreementComputerAttachment
设为 @Embeddable
。
一个@Embeddable
不像一个实体没有独立的身份(没有@ID
)。在此处进一步查看:
What is difference between @Entity and @embeddable
@Entity
public class CustomerAgreement {
@ElementCollection
@JoinTable(name="...", joinColumn = "id")
private List<CustomerAgreementComputerAttachment> attachments;
}
和
@Embeddable
public class CustomerAgreementComputerAttachments {
//No back reference to CustomerAgreement
//Other fields as required.
}
客户说子 Table 中不需要主键。所以 Child table 有两列 "ID" 和 "Value",其中 ID 可以重复。
当我删除@Id 然后休眠说 "No identifier specified for entity"
当我在代码中保留@Id 时,hibernate 说 "javax.persistence.EntityExistsException: a different object with the same identifier value was already associated with the session";在坚持的同时
关键是我需要保留@Id,但如何使用@Id 注释在一个会话中保留两个相同的ID。
代码如下:
主要实体:
public class CustomerAgreement implements Serializable {
@OneToMany(mappedBy = "customerAgreement", orphanRemoval = true, fetch = FetchType.LAZY, cascade = {CascadeType.PERSIST})
private List<CustomerAgreementComputerAttachments> autoAttachComputersFromOrganizations;
组合实体:
public class CustomerAgreementComputerAttachments implements Serializable{
private static final long serialVersionUID = 1L;
@Id
@ManyToOne
@JoinColumn(name = "ID")
private CustomerAgreement customerAgreement;
主程序:
public static List<CustomerAgreement> create() {
List<CustomerAgreement> li = new ArrayList<CustomerAgreement>();
CustomerAgreement cAgreement = new CustomerAgreement();
cAgreement.setId(2222l);
cAgreement.setName("Tillu");;
cAgreement.setCustomerId("140");
List<CustomerAgreementComputerAttachments> catl = new ArrayList<>();
CustomerAgreementComputerAttachments catt = new CustomerAgreementComputerAttachments();
catt.setAttachmentValue("TEST");
catt.setCustomerAgreement(cAgreement);
CustomerAgreementComputerAttachments tatt = new CustomerAgreementComputerAttachments();
tatt.setAttachmentValue("TESTy");
tatt.setCustomerAgreement(cAgreement);
catl.add(catt);
catl.add(tatt);
cAgreement.setAutoAttachComputersFromOrganizations(catl);
li.add(cAgreement);
return li;
}
public static void main(String[] args) {
EntityManagerFactory emf = Persistence.createEntityManagerFactory("IntegratorMasterdataPU");
em = emf.createEntityManager();
em.getTransaction().begin();
for(CustomerAgreement ca: create()) {
em.persist(ca);
}
em.getTransaction().commit();
}
实体必须可由唯一键识别。这不需要对应于任何数据库主键,但必须有一个或多个可用于标识实体的唯一列。
如果这不可能,那么您需要将 CustomerAgreementComputerAttachment
设为 @Embeddable
。
一个@Embeddable
不像一个实体没有独立的身份(没有@ID
)。在此处进一步查看:
What is difference between @Entity and @embeddable
@Entity
public class CustomerAgreement {
@ElementCollection
@JoinTable(name="...", joinColumn = "id")
private List<CustomerAgreementComputerAttachment> attachments;
}
和
@Embeddable
public class CustomerAgreementComputerAttachments {
//No back reference to CustomerAgreement
//Other fields as required.
}