每n步执行一次while循环

Question

如何让for循环中，每执行7次循环后，执行某个动作，然后循环继续执行7次？

现在我有一个循环使用 Python + applescript 执行一些操作。我尝试使用 while 来创建一个条件，该条件应在每 7 个步骤后执行，然后使用 excel 继续循环。循环正常，一切正常。但是在while开始执行的那一刻——它不想从头开始循环，它想一直执行while，因为count变量从excel文件中取行。如何解决？

from subprocess import Popen, PIPE
import xlrd

def main():
    apple_script = '''
         code
       '''
    workbook = xlrd.open_workbook('test.xlsx')
    sheet = workbook.sheet_by_index(0)
    count = 1
    for cell in sheet.col(0):
        p = Popen(['osascript', '-'], stdin=PIPE, stdout=PIPE, stderr=PIPE, universal_newlines=True)
        stdout, stderr = p.communicate(apple_script)
        count += 1
        while count >= 7:
            app_script = '''
                 code
                '''
            p = Popen(['osascript', '-'], stdin=PIPE, stdout=PIPE, stderr=PIPE, universal_newlines=True)
            stdout, stderr = p.communicate(app_script)
            break
if __name__ == "__main__":
    main()

Answer 1

这是一种方法，每个循环保留一个计数器，然后您可以 %7 这个数字并在每 7 个循环中执行一个过程：

x=0
while x < 50:
   if x % 7 == 0:
      print(f"Loop for Every Seven: {x}")
   x = x + 1

输出：

Loop for Every Seven: 0
Loop for Every Seven: 7
Loop for Every Seven: 14
Loop for Every Seven: 21
Loop for Every Seven: 28
Loop for Every Seven: 35
Loop for Every Seven: 42
Loop for Every Seven: 49

Answer 2

count=1
while count >= 7:
   if count % 7 == 0:
      print(count)
   count = count + 1

输出：

每n步执行一次while循环

The execution of the while loop after every n steps

python

applescript

for-loop

while-loop

python-3.x