Slack 事件 API：针对自己的机器人用户的响应发布（多次）事件

Question

我似乎在通过 Slack 事件响应传入消息时遇到问题 API (im.message event)。

当用户（在本例中 UQ364CBPF）向我的 App Home 发送消息时，事件 API 正确地将事件发布到我的后端（=第一行下面的日志）。
我用 HTTP 200 OK 响应事件，在我的代码中（见下文），我触发了我的机器人用户的响应。
此响应已在 Slack 中正确发送。

但是：在那之后，事件API不断发布我自己的机器人用户已经发布消息的事件这个频道...

此外，事件通常只发布 3 次，这些事件只会不停地发布。尽管机器人用户只在 Slack 中发送了一条响应消息。

User UQ364CBPF has posted message: I'm typing a message to my Slack bot. in DQ5FF35N2 of channel type: im
[26/Dec/2019 15:16:30] "POST /slack/events/ HTTP/1.1" 200 0
User UQ5529KTR has posted message: Thank you for your message! We will get back to you soon! in DQ5FF35N2 of channel type: im
[26/Dec/2019 15:16:32] "POST /slack/events/ HTTP/1.1" 200 0
User UQ5529KTR has posted message: Thank you for your message! We will get back to you soon! in DQ3KX0NPJ of channel type: im
[26/Dec/2019 15:16:33] "POST /slack/events/ HTTP/1.1" 200 0
User UQ5529KTR has posted message: Thank you for your message! We will get back to you soon! in DQ3KX0NPJ of channel type: im
[26/Dec/2019 15:16:35] "POST /slack/events/ HTTP/1.1" 200 0
User UQ5529KTR has posted message: Thank you for your message! We will get back to you soon! in DQ3KX0NPJ of channel type: im
[26/Dec/2019 15:16:37] "POST /slack/events/ HTTP/1.1" 200 0
User UQ5529KTR has posted message: Thank you for your message! We will get back to you soon! in DQ3KX0NPJ of channel type: im
[26/Dec/2019 15:16:39] "POST /slack/events/ HTTP/1.1" 200 0
User UQ5529KTR has posted message: Thank you for your message! We will get back to you soon! in DQ3KX0NPJ of channel type: im
[26/Dec/2019 15:16:40] "POST /slack/events/ HTTP/1.1" 200 0
User UQ5529KTR has posted message: Thank you for your message! We will get back to you soon! in DQ3KX0NPJ of channel type: im
[26/Dec/2019 15:16:42] "POST /slack/events/ HTTP/1.1" 200 0
User UQ5529KTR has posted message: Thank you for your message! We will get back to you soon! in DQ3KX0NPJ of channel type: im
[26/Dec/2019 15:16:43] "POST /slack/events/ HTTP/1.1" 200 0
User UQ5529KTR has posted message: Thank you for your message! We will get back to you soon! in DQ3KX0NPJ of channel type: im

在我的代码中，这是处理 Slack 事件的更大函数的一部分，相关部分：

@csrf_exempt
def slack_events(request):
    if request.method == 'POST':
        json_data = json.loads(request.body)
        event_callback_type = json_data['event']['type']
        if event_callback_type == 'message':
                user_id = json_data['event']['user']
                text = json_data['event']['text']
                channel_id = json_data['event']['channel']
                channel_type = json_data['event']['channel_type']
                timestamp = json_data['event']['ts']
                print ('User ' + user_id + ' has posted message: ' + text + ' in ' + channel_id + ' of channel type: ' + channel_type)
                slack_message_received(user_id, channel_id, channel_type, team_id, timestamp, text)
                return HttpResponse(status=200)

此处（或函数 slack_message_received 中）没有任何内容可以触发此循环流。

所以

1. Slack 用这些东西来轰炸我是不是很奇怪 POST 来自我自己的机器人用户的请求？

2。除了过滤掉我自己的 Bot 用户 ID 并在后端忽略这些请求之外，我可以避免这种行为吗？

Answer 1

事件的标准行为 API 您的机器人将接收所有消息事件，包括来自它自己的帖子。通过对它们做出反应，你已经创建了无限循环。

要解决此问题，您需要停止对机器人自己的消息做出反应，方法是按照您在 #2 中的建议将其过滤掉。这是标准方法。

最简单的方法是过滤掉所有机器人消息，如果您不需要收听其他机器人的话。然后您可以忽略所有具有 subtype 属性的消息。或者，您当然可以从您自己的机器人中过滤我们的消息。

Answer 2

我遇到了同样的问题。但是当我打印请求时，我找不到 subtype 所以上面的解决方案对我不起作用。 log detail showing what is in the request I receive. There was no subtype

相反，我注意到来自机器人的消息有 bot_id 而来自用户的消息没有。因此，我的解决方案是这样的：

    @slack_events_adapter.on("message")
    def say_hello(event_data):
       print('EVENT_DATA')
       print(event_data)
       message = event_data['event']

       # if the incoming message contains "hello" NOT CASE SENSITIVE, then respond with a designed message
       # "subtype" doesnt help to filter bot's message event and user's message event
       if message.get('bot_id') is None and 'hello' in ((message.get('text')).lower()):
           channel_id = message['channel']
           user = message['user']
           message = "Hello <@%s>! :tada:" % user
           slack_web_client.chat_postMessage(channel=channel_id, text=message)
       else:
           return

Answer 3

正如@Phoebe 所说 - 在使用

检索事件时

slack_message.get('event')

我没有找到密钥 bot_id。我认为这是 Slack Events api.

的一个问题

Slack 事件 API：针对自己的机器人用户的响应发布（多次）事件

Slack Events API: Events are posted (multiple times) for responses of own bot user

django

events

bots

slack-api

slack