Subtracting datetime, one column from another. Getting error: unsupported operand type(s) for -: 'str' and 'str'

Question

Jupyter 笔记本Python3.7
从一列中减去另一列的日期时间
df['dropoff_datetime']
df['pickup_datetime']
出现错误：不支持的操作数类型 - 'str' 和 'str'
求助！

代码：

import numpy as np
df['trip_minutes'] = df['dropoff_datetime'] - df['pickup_datetime']
df['trip_minutes'] = df['trip_minutes']/np.timedelta64(1,'m')

Answer 1

您遇到此错误是因为您正在尝试计算不受支持的两个字符串的总和。

df
  dropoff_datetime pickup_datetime
0         00:07:56        00:10:44


df['dropoff_datetime'] - df['pickup_datetime']
Traceback (most recent call last):
TypeError: unsupported operand type(s) for -: 'str' and 'str'

要计算时差，您需要将数据框中的列设置为timedelta。然后你就可以进行计算了；

df['dropoff_datetime'] = pd.to_timedelta(df['dropoff_datetime'])
df['pickup_datetime'] = pd.to_timedelta(df['pickup_datetime'])

df['dropoff_datetime'] - df['pickup_datetime']

0   -1 days +23:57:12
dtype: timedelta64[ns]

编辑：

根据您更新的 df 信息，以上内容不适用于您指定的数据。但是，您可以运行 DF 中每行下面的计算来检索值；

trip_minutes = datetime.strptime(df['dropoff_datetime'][0], '%d-%m-%Y %H:%M:%S %p') - datetime.strptime(df['pickup_datetime'][0], '%d-%m-%Y %H:%M:%S %p')

datetime.timedelta(seconds=815)

这会在您计算差异时将您的字符串转换为日期时间对象。

Subtracting datetime, one column from another. Getting error: unsupported operand type(s) for -: 'str' and 'str'

Subtracting datetime, one column from another. Getting error: unsupported operand type(s) for -: 'str' and 'str'

python

numpy

python-datetime

pandas

jupyter