Oracle 中的嵌套 case 语句

Question

过去几个小时我一直盯着这个看，但我看不出我在哪里放弃了这个查询，代码已经匿名化，所以请原谅替换标识符：

select count (distinct(case when status not in ('Larry','Curly','Moe','Shemp')
                       then case when(case when 
                       (MIN(case when status in ('Larry','Curly','Moe','Shemp')
                            then case when to_char(my_date,'YYYY') = 1900
                            then my_dttm
                            else my_dttm
                            end
                            end) <= '18-nov-2019')
            and
                       (MIN(case when status in ('Larry','Curly','Moe','Shemp')
                            then case when to_char(my_date,'YYYY') = 1900
                            then my_dttm
                            else my_dttm
                            end
                            end) >= '1-oct-2019')
            then
                        MIN(case when status in ('Larry','Curly','Moe','Shemp')
                            then case when to_char(my_date,'YYYY') = 1900
                            then my_dttm
                            else my_dttm
                            end
                            end)end) is null
           then case when to_date >= '1-oct-2019' and from_date <= '18-nov-2019' then c_id end
)) from my_table; -- error code references this line

我收到的错误代码：ORA-00905：缺少关键字 00905.00000 - "missing keyword"。我在这个网站上搜索了类似的东西，但找不到适合我具体情况的东西。帮助将不胜感激。谢谢

Answer 1

以下两个case语句没有"end"

select count (distinct(case when status not in ('Larry','Curly','Moe','Shemp') then case when(case when (MIN(case when status in ('Larry','Curly','Moe','Shemp') then case when to_char(my_date,'YYYY') = 1900 then my_dttm else my_dttm end end) <= '18-nov-2019') and (MIN(case when status in ('Larry','Curly','Moe','Shemp') then case when to_char(my_date,'YYYY') = 1900 then my_dttm else my_dttm end end) >= '1-oct-2019') then MIN(case when status in ('Larry','Curly','Moe','Shemp') then case when to_char(my_date,'YYYY') = 1900 then my_dttm else my_dttm end end)end) is null then case when to_date >= '1-oct-2019' and from_date <= '18-nov-2019' then c_id end end end )) from my_table;

case when status not in ('Larry','Curly','Moe','Shemp')
then case when(case when

Answer 2

您在错误行缺少两个 END 关键字。

查看以下内容：

SELECT
    COUNT(DISTINCT(CASE
        WHEN STATUS NOT IN(
            'Larry', 'Curly', 'Moe', 'Shemp'
        ) THEN CASE
            WHEN(CASE
                WHEN(MIN(CASE
                    WHEN STATUS IN(
                        'Larry', 'Curly', 'Moe', 'Shemp'
                    ) THEN CASE
                        WHEN TO_CHAR(MY_DATE, 'YYYY') = 1900 THEN MY_DTTM
                        ELSE MY_DTTM
                    END
                END) <= '18-nov-2019')
                    AND(MIN(CASE
                    WHEN STATUS IN(
                        'Larry', 'Curly', 'Moe', 'Shemp'
                    ) THEN CASE
                        WHEN TO_CHAR(MY_DATE, 'YYYY') = 1900 THEN MY_DTTM
                        ELSE MY_DTTM
                    END
                END) >= '1-oct-2019') THEN MIN(CASE
                    WHEN STATUS IN(
                        'Larry', 'Curly', 'Moe', 'Shemp'
                    ) THEN CASE
                        WHEN TO_CHAR(MY_DATE, 'YYYY') = 1900 THEN MY_DTTM
                        ELSE MY_DTTM
                    END
                END)
            END) IS NULL THEN CASE
                WHEN TO_DATE >= '1-oct-2019'
                     AND FROM_DATE <= '18-nov-2019' THEN C_ID
            END -- this is missing in your code
        END -- this is missing in your code
    END))
FROM
    MY_TABLE;

干杯！！

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