获取 Python 中特定节点的所有子节点

Question

我有以下 example.xml 结构：

<ParentOne>
   <SiblingOneA>This is Sibling One A</SiblingOneA>
   <SiblingTwoA>
      <ChildOneA>Value of child one A</ChildOneA>
      <ChildTwoA>Value of child two A</ChildTwoA>
   </SiblingTwoA>
</ParentOne>

<ParentTwo>
   <SiblingOneA>This is a different value for Sibling one A</SiblingOneA>
   <SiblingTwoA>
      <ChildOneA>This is a different value for Child one A</ChildOneA>
      <ChildTwoA>This is a different value for Child Two A</ChildTwoA>
   </SiblingTwoA>
</ParentTwo>

 <ParentThree>
   <SiblingOneA>A final value for Sibling one A</SiblingOneA>
   <SiblingTwoA>
      <ChildOneA>A final value for Child one A</ChildOneA>
      <ChildTwoA>A final value for Child one A</ChildTwoA>
   </SiblingTwoA>
</ParentThree>

我的主要要求是遍历每个节点，当有问题的当前节点是 "SiblingOneA" 时，代码会检查直接相邻的兄弟节点是否是 "SiblingTwoA" .如果是这样，那么它应该检索所有子节点（包括元素本身和元素内的值）。

到目前为止，这是我的代码：

from lxml import etree
XMLDoc = etree.parse('example.xml')
rootXMLElement = XMLDoc.getroot()
tree = etree.parse('example.xml)
import os

for Node in XMLDoc.xpath('//*'):
   if os.path.basename(XMLDoc.getpath(Node)) == "SiblingOneA":
      if Node.getnext() is not None:
         if Node.getnext().tag == "SiblingTwoA":
            #RETRIEVE ALL THE CHILDREN ELEMENTS OF THAT SPECIFIC SiblingTwoA NODE AND THEIR VALUES

您可能已经从我上面的代码中推断出，我不知道用什么来代替注释来检索 "SiblingTwoA" 节点的所有子元素和值。此外，这段代码应该 而不是 return 整个树结构中 SiblingTwoA 节点的所有子元素，而只是有问题的那个（即那个 return 从 Node.getnext() 元素编辑）。您还会注意到许多元素是相同的，但它们的值不同。

编辑：

我已经能够使用 Node.getnext().getchildren() 检索相关元素的子元素。但是，这个return是列表形式的信息，如：

[<Element ChildOneA at 0x101a95870>, <Element ChildTwoA at 0x101a958c0>]
[<Element ChildOneA at 0x101a95a50>, <Element ChildTwoA at 0x101a95aa0>]
[<Element ChildOneA at 0x101a95c30>, <Element ChildTwoA at 0x101a95c80>]

如何检索元素中的实际值？

例如，对于第一次迭代，我想要的输出类似于：

ChildOneA = Value of child one A

ChildTwoA = Value of child two A

Answer 1

我想生成一个简单的列表 (['Value of child one A', 'Value of child two A', 'This is a different value for Child one A', 'This is a different value for Child Two A', 'A final value for Child one A', 'A final value for Child one A']) 你可以使用

[child.xpath('string()') for sibling in doc.xpath('//SiblingTwoA[preceding-sibling::*[1][self::SiblingOneA]]') for child in sibling.xpath('*')]

要生成嵌套列表 ([['Value of child one A', 'Value of child two A'], ['This is a different value for Child one A', 'This is a different value for Child Two A'], ['A final value for Child one A', 'A final value for Child one A']])，您可以使用

[[child.xpath('string()') for child in sibling.xpath('*')] for sibling in doc.xpath('//SiblingTwoA[preceding-sibling::*[1][self::SiblingOneA]]')]

获取 Python 中特定节点的所有子节点

Get all children of specific node in Python

python

xml

lxml