从 psycopg2 fetchall 函数输出创建逗号分隔的字符串

Question

使用 python psycopg2，我有以下代码：

conn = psycopg2.connect(host=endpoint ,database=database, user=user, password=password)
cur = conn.cursor()
cur.execute("select * from pg_stat_activity;")
records = cur.fetchall()
for record in records:
    print(record)

该代码转储如下记录：

(16391, 'app', 9233, 16389, 'app', '', '10.20.12.17', None, 55204, datetime.datetime(2020, 1, 14, 1, 43, 19, 214161, tzinfo=psycopg2.tz.FixedOffsetTimezone(offset=0, name=None)), datetime.datetime(2020, 1, 14, 1, 43, 19, 410905, tzinfo=psycopg2.tz.FixedOffsetTimezone(offset=0, name=None)), datetime.datetime(2020, 1, 14, 1, 43, 19, 442050, tzinfo=psycopg2.tz.FixedOffsetTimezone(offset=0, name=None)), datetime.datetime(2020, 1, 14, 1, 43, 19, 442051, tzinfo=psycopg2.tz.FixedOffsetTimezone(offset=0, name=None)), None, None, 'active', None, '22332', 'select * from pg_stat_activity;')
...
...

它显示如下函数调用：

datetime.datetime(2020, 1, 14, 1, 43, 19, 214161, tzinfo=psycopg2.tz.FixedOffsetTimezone(offset=0, name=None))

然而，我真正想要的是它显示函数的字符串输出，如：

2019-12-20 01:59:33.270944+00

我怎样才能让 psycopg2 为我显示这个？

谢谢。

Answer 1

使用 datetime.strftime() 格式化日期时间元素。

for record in records:
    l = list(record[0:9])
    # format times in elements 9-12
    for i in range(9, 13):
        l.append(record[i].strftime('%Y-%m-%d %H:%M:%S.%f%z')
    l += record[13:]
    print(l)

从 psycopg2 fetchall 函数输出创建逗号分隔的字符串

Create comma seperated string from psycopg2 fetchall function output

python

psycopg2

python-3.x