使用 tkinter 编辑文本时显示下拉组合框

Show combobox drop down while editing text using tkinter

是否可以在下拉菜单打开时使组合框可编辑? 我还没有找到任何解决方案。 我想让它更像 Google 搜索,但使用组合框。

Question: Show Combobox PopdownWindow, while editing text

此示例将 ttk.Combobox 扩展为以下内容:

  • 键入时显示 PopdownWindow
  • 在按键时打开 PopdownWindow '<Down>'
  • 如果在 Listbox
  • 中的第一项,则在按键 '<Up' 时关闭 PopdownWindow

参考


  1. 继承自ttk.Combox

    import tkinter as tk
    import tkinter.ttk as ttk
    
    
    class Combobox(ttk.Combobox):
    
  2. Helper 函数,将内部 ToplevelListbox 映射到 tkinter 对象。

    WARNING: This uses Tk/Tcl internals, which could change without notice.
    This may working only with the tested Tk/Tcl version!

    def _tk(self, cls, parent):
        obj = cls(parent)
        obj.destroy()
        if cls is tk.Toplevel:
            obj._w = self.tk.call('ttk::combobox::PopdownWindow', self)
        else:
            obj._w = '{}.{}'.format(parent._w, 'f.l')
        return obj
    
  3. 初始化对象,获取内部引用并绑定到按键事件

    def __init__(self, parent, **kwargs):
        super().__init__(parent, **kwargs)
        self.popdown = self._tk(tk.Toplevel, parent)
        self.listbox = self._tk(tk.Listbox, self.popdown)
    
        self.bind("<KeyPress>", self.on_keypress, '+')
        self.listbox.bind("<Up>", self.on_keypress)
    
  4. 用于显示或隐藏 PopdownWindow 并设置键盘焦点的按键处理程序。

    def on_keypress(self, event):
        if event.widget == self:
            state = self.popdown.state()
    
            if state == 'withdrawn' \
                    and event.keysym not in ['BackSpace', 'Up']:
                self.event_generate('<Button-1>')
                self.after(0, self.focus_set)
    
            if event.keysym == 'Down':
                self.after(0, self.listbox.focus_set)
    
        else:  # self.listbox
            curselection = self.listbox.curselection()
    
            if event.keysym == 'Up' and curselection[0] == 0:
                self.popdown.withdraw()
    
    

    Usage:

    class App(tk.Tk):
        def __init__(self):
            super().__init__()
    
            values = ('one', 'two', 'three', 'four', 'five', 'six', 'seven')
    
            self.cb = Combobox(self, value=values)
            self.cb.grid(row=0, column=0)
    
    
    if __name__ == "__main__":
        App().mainloop()
    
    

    测试 Python:3.5 - 'TclVersion':8.6 'TkVersion':8.6