Java - 使用 HtmlUnit 发送 post 请求
Java - Sending a post request with HtmlUnit
在这方面找不到任何帮助,但我一直在尝试使用 HtmlUnit 发送 post 请求。我的代码是:
final WebClient webClient = new WebClient();
// Instead of requesting the page directly we create a WebRequestSettings object
WebRequest requestSettings = new WebRequest(
new URL("www.URLHERE.com"), HttpMethod.POST);
// Then we set the request parameters
requestSettings.setRequestParameters(new ArrayList());
requestSettings.getRequestParameters().add(new NameValuePair("name", "value"));
// Finally, we can get the page
HtmlPage page = webClient.getPage(requestSettings);
有没有更简单的方法可以执行 POST 请求?
有 n 个可能的库,您可以使用它们来调用其余 Web 服务。
1) Apache Http 客户端
2) 从 Square 改造
3) 来自 google
的截击
我用过Http Apache 客户端和Retrofit。两个都很棒。
这是 Apache HTTP 客户端发送 Post 请求的代码示例
String token = null;
HttpClient httpClient = HttpClientBuilder.create().build();
HttpPost postRequest = new HttpPost(LOGIN_URL);
StringBuilder sb = new StringBuilder();
sb.append("{\"userName\":\"").append(user).append("\",").append("\"password\":\"").append(password).append("\"}");
String content = sb.toString();
StringEntity input = new StringEntity(content);
input.setContentType("application/json");
postRequest.setHeader("Content-Type", "application/json");
postRequest.setHeader("Accept", "application/json");
postRequest.setEntity(input);
HttpResponse response = httpClient.execute(postRequest);
if (response.getStatusLine().getStatusCode() != 201)
{
throw new RuntimeException("Failed : HTTP error code : " + response.getStatusLine().getStatusCode());
}
Header[] headers = response.getHeaders("X-Auth-Token");
if (headers != null && headers.length > 0)
{
token = headers[0].getValue();
}
return token;
这是怎么做的
public void post() throws Exception
{
URL url = new URL("YOURURL");
WebRequest requestSettings = new WebRequest(url, HttpMethod.POST);
requestSettings.setAdditionalHeader("Accept", "*/*");
requestSettings.setAdditionalHeader("Content-Type", "application/x-www-form-urlencoded; charset=UTF-8");
requestSettings.setAdditionalHeader("Referer", "REFURLHERE");
requestSettings.setAdditionalHeader("Accept-Language", "en-US,en;q=0.8");
requestSettings.setAdditionalHeader("Accept-Encoding", "gzip,deflate,sdch");
requestSettings.setAdditionalHeader("Accept-Charset", "ISO-8859-1,utf-8;q=0.7,*;q=0.3");
requestSettings.setAdditionalHeader("X-Requested-With", "XMLHttpRequest");
requestSettings.setAdditionalHeader("Cache-Control", "no-cache");
requestSettings.setAdditionalHeader("Pragma", "no-cache");
requestSettings.setAdditionalHeader("Origin", "https://YOURHOST");
requestSettings.setRequestBody("REQUESTBODY");
Page redirectPage = webClient.getPage(requestSettings);
}
您可以根据需要对其进行自定义。 Add/remove headers, add/remove 请求 body, 等等...
在这方面找不到任何帮助,但我一直在尝试使用 HtmlUnit 发送 post 请求。我的代码是:
final WebClient webClient = new WebClient();
// Instead of requesting the page directly we create a WebRequestSettings object
WebRequest requestSettings = new WebRequest(
new URL("www.URLHERE.com"), HttpMethod.POST);
// Then we set the request parameters
requestSettings.setRequestParameters(new ArrayList());
requestSettings.getRequestParameters().add(new NameValuePair("name", "value"));
// Finally, we can get the page
HtmlPage page = webClient.getPage(requestSettings);
有没有更简单的方法可以执行 POST 请求?
有 n 个可能的库,您可以使用它们来调用其余 Web 服务。
1) Apache Http 客户端 2) 从 Square 改造 3) 来自 google
的截击我用过Http Apache 客户端和Retrofit。两个都很棒。
这是 Apache HTTP 客户端发送 Post 请求的代码示例
String token = null;
HttpClient httpClient = HttpClientBuilder.create().build();
HttpPost postRequest = new HttpPost(LOGIN_URL);
StringBuilder sb = new StringBuilder();
sb.append("{\"userName\":\"").append(user).append("\",").append("\"password\":\"").append(password).append("\"}");
String content = sb.toString();
StringEntity input = new StringEntity(content);
input.setContentType("application/json");
postRequest.setHeader("Content-Type", "application/json");
postRequest.setHeader("Accept", "application/json");
postRequest.setEntity(input);
HttpResponse response = httpClient.execute(postRequest);
if (response.getStatusLine().getStatusCode() != 201)
{
throw new RuntimeException("Failed : HTTP error code : " + response.getStatusLine().getStatusCode());
}
Header[] headers = response.getHeaders("X-Auth-Token");
if (headers != null && headers.length > 0)
{
token = headers[0].getValue();
}
return token;
这是怎么做的
public void post() throws Exception
{
URL url = new URL("YOURURL");
WebRequest requestSettings = new WebRequest(url, HttpMethod.POST);
requestSettings.setAdditionalHeader("Accept", "*/*");
requestSettings.setAdditionalHeader("Content-Type", "application/x-www-form-urlencoded; charset=UTF-8");
requestSettings.setAdditionalHeader("Referer", "REFURLHERE");
requestSettings.setAdditionalHeader("Accept-Language", "en-US,en;q=0.8");
requestSettings.setAdditionalHeader("Accept-Encoding", "gzip,deflate,sdch");
requestSettings.setAdditionalHeader("Accept-Charset", "ISO-8859-1,utf-8;q=0.7,*;q=0.3");
requestSettings.setAdditionalHeader("X-Requested-With", "XMLHttpRequest");
requestSettings.setAdditionalHeader("Cache-Control", "no-cache");
requestSettings.setAdditionalHeader("Pragma", "no-cache");
requestSettings.setAdditionalHeader("Origin", "https://YOURHOST");
requestSettings.setRequestBody("REQUESTBODY");
Page redirectPage = webClient.getPage(requestSettings);
}
您可以根据需要对其进行自定义。 Add/remove headers, add/remove 请求 body, 等等...