如何使用 python 中的 BeautifulSoup 获取第二个跨度？

Question

我正在尝试获取此 div 和其他类似内容（如下所示）中的第二个跨度值

<div class="C(#959595) Fz(11px) D(ib) Mb(6px)">
    <span>VALUE 1</span>
    <i aria-hidden="true" class="Mx(4px)">•</i>
    <span>TRYING TO GET THIS</span>
</div>

我已经尝试查看类似的堆栈帖子，但我仍然无法弄清楚如何解决这个问题。这是我当前的代码：

time = soup.find_all('div', {'class': 'C(#959595) Fz(11px) D(ib) Mb(6px)'})
    for i in time:
        print(i.text) #this prints VALUE 1 x amount of times (there are multiple divs)

我试过 i.span、i.contents、i.children 等。非常感谢任何帮助，谢谢！

Answer 1

试试这个

from io import StringIO
from bs4 import BeautifulSoup as bs

data = """<div class="C(#959595) Fz(11px) D(ib) Mb(6px)">
    <span>VALUE 1</span>
    <i aria-hidden="true" class="Mx(4px)">•</i>
    <span>TRYING TO GET THIS</span>
</div>
<div class="another class">
    <span>VALUE 1</span>
    <i aria-hidden="true" class="Mx(4px)">•</i>
    <span>TRYING TO GET THIS</span>
</div>"""

soup = bs(StringIO(data))
spans = soup.select('div[class="C(#959595) Fz(11px) D(ib) Mb(6px)"] > span')
print(spans[1].text)

Answer 2

你基本上已经做到了，你只需要在每个 div (find_next):

中获得第二个跨度

soup = BeautifulSoup(HTML, 'html.parser')
divs = soup.find_all('div', {'class': 'C(#959595) Fz(11px) D(ib) Mb(6px)'})
for div in divs:
    # want the second span in the div
    span = div.find_next('span').find_next('span')
    print(span.string)

Answer 3

div= soup.find_all('div',class_='C(#959595) Fz(11px) D(ib) Mb(6px)')
[x.get_text() for x in div[0].find_all('span')]

#op

Out[17]:
['VALUE 1', 'TRYING TO GET THIS']

Answer 4

有几种方法可以获得您想要的值。

from simplified_scrapy.simplified_doc import SimplifiedDoc
html='''
<div class="C(#959595) Fz(11px) D(ib) Mb(6px)">
    <span>VALUE 1</span>
    <i aria-hidden="true" class="Mx(4px)">•</i>
    <span>TRYING TO GET THIS</span>
</div>
'''
doc = SimplifiedDoc(html)
divs = doc.getElementsByClass('C(#959595) Fz(11px) D(ib) Mb(6px)')
for div in divs:
  value = div.getElementByTag('span',start='</span>') # Use start to skip the first
  print (value)
  value = div.getElementByTag('span',before='<span>',end=len(div.html)) # Locate the last
  print (value)
  value = div.i.next # Use <i> to locate
  print (value)
  value = div.spans[-1]
  print (value)
  print (value.text)

结果：

{'tag': 'span', 'html': 'TRYING TO GET THIS'}
{'tag': 'span', 'html': 'TRYING TO GET THIS'}
{'tag': 'span', 'html': 'TRYING TO GET THIS'}
{'tag': 'span', 'html': 'TRYING TO GET THIS'}
TRYING TO GET THIS

如何使用 python 中的 BeautifulSoup 获取第二个跨度？

How can I get the second span using BeautifulSoup in python?

python

beautifulsoup

html-parsing

web-scraping