How to get else option that prints out ("This is not a number"). Strings and Ints HELP! (ValueError: invalid literal for int() with base 10:)

Question

错误信息： ValueError：以 10 为底的 int() 无效文字：“

Thanks

# Name
name = input("Enter Name: ")
# Age
age = int(input("Enter Age: "))

if age == str():
    print("Not a Number!")
else:
    pass


# Age - 100 equals
subage = 100 - age

# Take the result of previous expression and add to year.
age100 = subage + 2020

# Print out results

print(name,"! " "You will be 100 years of age in the year of: ", age100)

只是写了更多，这样我就可以把这个东西送到 post。 sdfsdff sfsdf

Answer 1

将 age = int(input("Enter Age: ")) 放在 try 块中，如果发生错误，则在其后跟一个 except 块：

try:
    age = int(input("Enter Age: "))
    # Age - 100 equals
    subage = 100 - age

    # Take the result of previous expression and add to year.
    age100 = subage + 2020

    # Print out results

    print(name,"! " "You will be 100 years of age in the year of: ", age100)
except ValueError:
    print(“This is not a number”)