比较 sql 服务器中相同 table 和 return 副本的每条记录

Question

我 table 喜欢 below.I 想要得到重复的 records.Here 如果 date2 和 date4 具有相同的日期或日期在彼此之间小于或等于 10 天的条件那么记录是重复的。我在 DB.Showing 中有大约 2000 条记录，这里有几个示例。 Date1 可以忽略。它可能是相同的日期，也可能不同。

ID Number   Code Type   date1     Date2       date3        Date4     status   shortname     CP      deferred
1  EO2      C    TO   9/20/2000  9/1/2010   9/18/2010   9/1/2010     Archi    Ordinary  58.65586    0
2  EO2      C    TO   9/20/2000  9/5/2010   9/18/2010   9/5/2010     Archi    Ordinary  58.65586    0
3  EO2      C    TO   9/21/2000  9/10/2010  9/18/2010   9/10/2010    Archi    Ordinary  58.65586    0
4  EO2      C    TO   9/21/2000  9/24/2010  9/18/2010   9/24/2010    Archi    Ordinary  58.65586    0

我写了下面的查询：

select * from T a
join T b on a.ID = b.ID
where a.[Number] = b.[Number] and a.ID >1

此外，我绑定了这个：

SELECT * FROM T a WHERE a.Id IN (SELECT b.Id FROM T b)
EXCEPT
SELECT * FROM T a

问题是我无法找到一种方法，其中每一行都可以与上述日期相互比较 condition.I 应该得到如下所示的重复结果：

Number  Code Type   date1     Date2       date3        Date4     status   shortname     CP      deferred
EO2     C    TO   9/20/2000  9/1/2010   9/18/2010   9/1/2010     Archi    Ordinary  58.65586    0
EO2     C    TO   9/20/2000  9/5/2010   9/18/2010   9/5/2010     Archi    Ordinary  58.65586    0
EO2     C    TO   9/21/2000  9/10/2010  9/18/2010   9/10/2010    Archi    Ordinary  58.65586    0

请help.Thanks.

Answer 1

您可以使用 join 来搜索其他相同的行。 join 尝试根据 on 条件匹配右侧 table 的所有行。例如：

select  *
from    YourTable t1
join    YourTable t2
on      t1.ID < t2.ID -- Must be different rows
                      -- Smaller than presents the duplicates once
                      -- Otherwise you'd get both 1,3 and 3,1
        and abs(datediff(day, t1.date2, t2.date2)) <= 10
        and abs(datediff(day, t1.date4, t2.date4)) <= 10
        and t1.Number = t2.Number
        and t1.Code = t2.Code
        and -- So on for every column that should be equal

要忽略某个列，请在 on 条件中将其省略。

Answer 2

我就是这样解决的。感谢您的帮助。

select t1.Number,t1.Code,t1.Type,t1.date1,t1.Date2,t1.date3,t1.Date4,t1.stats,t1.shortn‌ame,t1.CP, t1.deferred 
from T t1 join T t2 on 1=1 and t2.Number = t1.Number and t2.Code = t1.Code and t2.Type = t1.Type and t2.deferred = t1.eferred and t2.CP = t1.CP and t2.status = t1.status and abs(datediff(day,t1.Date2,t2.Date2)) <=10 and abs(datediff(day,t1.date3,t2.date3)) <=10 and abs(datediff(day,t1.Date4,t2.Date4)) <=10 group by t1.Number, t1.Code,t1.Type , t1.date1, t1.Date2,t1.date3,t1.Date4 ,t1.status,t1.shortname,t1.CP, t1.deferred having count(*) > 1

比较 sql 服务器中相同 table 和 return 副本的每条记录

Compare each records of same table in sql server and return duplicates

sql-server

sql-server-2008

sql-server-2008-r2