如何获得列中负值的向下直方图？

Question

我有一列的值范围为 -10 到 +10。我想绘制一个直方图，其中负值频率向下显示，正值向上显示。如何做到这一点？

 df8$Difference
  [1]  -2   6   7  -8   6   5   2   4  -3   1   9   3  -4   2   6  -1  11   5   2   8  15
 [22]   0   9  -5   1  16  12  14  -7 -11  -8   1   1  11   6   3   2  -2   8  -5  NA  -5
 [43]   2  10   7   1   9  -5   7   4   5   9  NA  13  -1   2   5   6   9   4   0   3  -4
 [64]   3   2   4  14  -9  12   6   0   6   6  -5  -1  -6  11   2   3   3   5   1  -5   6
 [85]  19  15  -4   9  -1  -4  -4 -10  NA  NA  NA   0   0  15   7 -10   2   0  -5  -5  10
[106]  -2  -8  18   1  -1   7  -5  -9  -6 -18  11  -1  NA  11  -4   7   5  20   3   2   0
[127]   2   2  11  -2  -5   0   6  -2   6  -2  -5  -1  -5  -6   3  -1  -9  -1   9  NA  -6
[148]   4  -5   8   0  -2   1   9   3   9  -3   2   8   0   2  -4   6   4  -5

Answer 1

可以直接操作直方图对象：

histo <- hist(df8$difference)

histo$counts[1:4] <- -histo$counts[1:4] 
plot(histo)

可重现的数据：

df8 <-  structure(list(difference = c(-2, 6, 7, -8, 6, 5, 2, 4, -3, 1, 
        9, 3, -4, 2, 6, -1, 11, 5, 2, 8, 15, 0, 9, -5, 1, 16, 12, 14, 
        -7, -11, -8, 1, 1, 11, 6, 3, 2, -2, 8, -5, NA, -5, 2, 10, 7, 
        1, 9, -5, 7, 4, 5, 9, NA, 13, -1, 2, 5, 6, 9, 4, 0, 3, -4, 3, 
        2, 4, 14, -9, 12, 6, 0, 6, 6, -5, -1, -6, 11, 2, 3, 3, 5, 1, 
        -5, 6, 19, 15, -4, 9, -1, -4, -4, -10, NA, NA, NA, 0, 0, 15, 
        7, -10, 2, 0, -5, -5, 10, -2, -8, 18, 1, -1, 7, -5, -9, -6, -18, 
        11, -1, NA, 11, -4, 7, 5, 20, 3, 2, 0, 2, 2, 11, -2, -5, 0, 6, 
        -2, 6, -2, -5, -1, -5, -6, 3, -1, -9, -1, 9, NA, -6, 4, -5, 8, 
        0, -2, 1, 9, 3, 9, -3, 2, 8, 0, 2, -4, 6, 4, -5)), 
        class = "data.frame", row.names = c(NA, -165L))

^{由 reprex package (v0.3.0)}

于 2020 年 2 月 21 日创建

如何获得列中负值的向下直方图？

How to get a downward directed histogram for negative values in a column?

r

histogram