setInterval不是每秒刷新一次数据
setInterval is not refresh data every second
var today = new Date();
var day = today.getDay()
var month = today.getMonth();
var year = today.getFullYear()
var date = (today.getMonth() + 1) + '/' + today.getDate() + '/' + today.getFullYear();
var time = today.getHours() + ":" + today.getMinutes() + ":" + today.getSeconds();
var dateTime = date + ' ' + time;
function dateTimeClock() {
$('#today').text(today);
$('#day').text(day);
$('#month').text(month);
$('#year').text(year);
$('#date').text(date);
$('#time').text(time);
$('#dateTime').text(dateTime);
}
setInterval(dateTimeClock, 1000);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.0.0/jquery.min.js"></script>
<p id="today"></p>
<p id="day"></p>
<p id="month"></p>
<p id="year"></p>
<p id="date"></p>
<p id="time"></p>
<p id="dateTime"></p>
有人可以告诉我为什么我的 setInterval 没有启动吗?
我希望我的数据每秒刷新一次。
日期变量是在时间间隔之外定义的,因此不会更新。要解决此问题,您必须将其包含在 dateTimeClock 函数中
function dateTimeClock() {
var today = new Date();
var day = today.getDay()
var month = today.getMonth();
var year = today.getFullYear()
var date = (today.getMonth() + 1) + '/' + today.getDate() + '/' + today.getFullYear();
var time = today.getHours() + ":" + today.getMinutes() + ":" + today.getSeconds();
var dateTime = date + ' ' + time;
$('#today').text(today);
$('#day').text(day);
$('#month').text(month);
$('#year').text(year);
$('#date').text(date);
$('#time').text(time);
$('#dateTime').text(dateTime);
}
setInterval(dateTimeClock, 1000);
您的时间变量只被调用一次,因此它们的值不会改变。
尝试从您的 dateTimeClock
函数中调用时间变量:
function dateTimeClock() {
var today = new Date();
var day = today.getDay()
var month = today.getMonth();
var year = today.getFullYear()
var date = (today.getMonth() + 1) + '/' + today.getDate() + '/' + today.getFullYear();
var time = today.getHours() + ":" + today.getMinutes() + ":" + today.getSeconds();
var dateTime = date + ' ' + time;
$('#today').text(today);
$('#day').text(day);
$('#month').text(month);
$('#year').text(year);
$('#date').text(date);
$('#time').text(time);
$('#dateTime').text(dateTime);
}
setInterval(dateTimeClock, 1000);
var today = new Date();
var day = today.getDay()
var month = today.getMonth();
var year = today.getFullYear()
var date = (today.getMonth() + 1) + '/' + today.getDate() + '/' + today.getFullYear();
var time = today.getHours() + ":" + today.getMinutes() + ":" + today.getSeconds();
var dateTime = date + ' ' + time;
function dateTimeClock() {
$('#today').text(today);
$('#day').text(day);
$('#month').text(month);
$('#year').text(year);
$('#date').text(date);
$('#time').text(time);
$('#dateTime').text(dateTime);
}
setInterval(dateTimeClock, 1000);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.0.0/jquery.min.js"></script>
<p id="today"></p>
<p id="day"></p>
<p id="month"></p>
<p id="year"></p>
<p id="date"></p>
<p id="time"></p>
<p id="dateTime"></p>
有人可以告诉我为什么我的 setInterval 没有启动吗?
我希望我的数据每秒刷新一次。
日期变量是在时间间隔之外定义的,因此不会更新。要解决此问题,您必须将其包含在 dateTimeClock 函数中
function dateTimeClock() {
var today = new Date();
var day = today.getDay()
var month = today.getMonth();
var year = today.getFullYear()
var date = (today.getMonth() + 1) + '/' + today.getDate() + '/' + today.getFullYear();
var time = today.getHours() + ":" + today.getMinutes() + ":" + today.getSeconds();
var dateTime = date + ' ' + time;
$('#today').text(today);
$('#day').text(day);
$('#month').text(month);
$('#year').text(year);
$('#date').text(date);
$('#time').text(time);
$('#dateTime').text(dateTime);
}
setInterval(dateTimeClock, 1000);
您的时间变量只被调用一次,因此它们的值不会改变。
尝试从您的 dateTimeClock
函数中调用时间变量:
function dateTimeClock() {
var today = new Date();
var day = today.getDay()
var month = today.getMonth();
var year = today.getFullYear()
var date = (today.getMonth() + 1) + '/' + today.getDate() + '/' + today.getFullYear();
var time = today.getHours() + ":" + today.getMinutes() + ":" + today.getSeconds();
var dateTime = date + ' ' + time;
$('#today').text(today);
$('#day').text(day);
$('#month').text(month);
$('#year').text(year);
$('#date').text(date);
$('#time').text(time);
$('#dateTime').text(dateTime);
}
setInterval(dateTimeClock, 1000);