从 firebase 调用数据需要完成处理程序吗?
Completion handler needed for calling data from firebase?
我正在尝试从 firebase 调用数据。问题是,数据嵌套很深,我认为我无法更改它。
所以我尝试从 firebase 调用值,然后我可以使用它来引用新值。
当我的for循环在调用下一阶段之前没有完成时,问题就出现了,这意味着我的下一阶段的字典计数为0,所以我的下一个函数没有被调用?
有没有办法充分做到这一点?
请帮忙?
这是我的代码:
func fetchBuyer(search: String, user: String, completion: @escaping ([Post]) -> (), withCancel cancel: ((Error) -> ())?) {
let ref = Database.database().reference().child("posts").child(user).child(search).child("purchases")
ref.observeSingleEvent(of: .value, with: { (snapshot) in
guard let dictionaries = snapshot.value as? [String: Any] else {
completion([])
return
}
let keys: [String] = dictionaries.map({ [=10=].key })
var newdictionaries = [String: String]()
for i in keys {
let newref = Database.database().reference().child("posts").child(user).child(search).child("purchases").child(i).child("purchaser")
newref.observeSingleEvent(of: .value, with: { (snapshot) in
newdictionaries[i] = snapshot.value as? String
print("THESE ARE MY PURCHASES ID-->", newdictionaries.values)///prints out ["-M0pTHtZXYUVQT7DCLj-", "-M0pU79uQCCnBunAEkJN"]
})
}
var buyerPosts = [Post]()
print("newdictionaries.count--->", newdictionaries.count)//this print is 0
newdictionaries.forEach({ (postId, value) in
Database.database().fetchPost(withUID: user, postId: postId, completion: { (post) in
buyerPosts.append(post)
if buyerPosts.count == newdictionaries.count{
completion(buyerPosts)
}
})
})
}) { (err) in
print("Failed to fetch posts for buyers:", err)
cancel?(err)
}
}
尝试的答案:
let g = DispatchGroup() //// 1
for i in keys{
g.enter() //// 2
let newref = Database.database().reference().child("posts").child(user).child(search).child("purchases").child(i).child("purchaser")
print("now")
newref.observeSingleEvent(of: .value, with: { (snapshot)
newdictionaries[i] = snapshot.value as? String
print("print new dictionaries-->", newdictionaries)
// complete here
Database.database().fetchPost(withUID: user, postId: newdictionaries[i]!, completion: { (post) in
buyerPosts.append(post)
g.leave() //////// 3
})
})
}
g.notify(queue: DispatchQueue.main) {
print("finished!!!")
completion(buyerPosts)
}
您需要一个调度组并嵌套调用
let g = DispatchGroup() //// 1
for i in keys{
g.enter() //// 2
let newref = Database.database().reference().child("posts").child(user).child(search).child("purchases").child(i).child("purchaser")
newref.observeSingleEvent(of: .value, with: { (snapshot)
newdictionaries[i] = snapshot.value as? String
// complete here
Database.database().fetchPost(withUID: user, postId: postId, completion: { (post) in
buyerPosts.append(post)
g.leave() //////// 3
})
})
}
/// 4
g.notfiy(queue.main) {
completion(buyerPosts)
}
我正在尝试从 firebase 调用数据。问题是,数据嵌套很深,我认为我无法更改它。
所以我尝试从 firebase 调用值,然后我可以使用它来引用新值。 当我的for循环在调用下一阶段之前没有完成时,问题就出现了,这意味着我的下一阶段的字典计数为0,所以我的下一个函数没有被调用?
有没有办法充分做到这一点?
请帮忙?
这是我的代码:
func fetchBuyer(search: String, user: String, completion: @escaping ([Post]) -> (), withCancel cancel: ((Error) -> ())?) {
let ref = Database.database().reference().child("posts").child(user).child(search).child("purchases")
ref.observeSingleEvent(of: .value, with: { (snapshot) in
guard let dictionaries = snapshot.value as? [String: Any] else {
completion([])
return
}
let keys: [String] = dictionaries.map({ [=10=].key })
var newdictionaries = [String: String]()
for i in keys {
let newref = Database.database().reference().child("posts").child(user).child(search).child("purchases").child(i).child("purchaser")
newref.observeSingleEvent(of: .value, with: { (snapshot) in
newdictionaries[i] = snapshot.value as? String
print("THESE ARE MY PURCHASES ID-->", newdictionaries.values)///prints out ["-M0pTHtZXYUVQT7DCLj-", "-M0pU79uQCCnBunAEkJN"]
})
}
var buyerPosts = [Post]()
print("newdictionaries.count--->", newdictionaries.count)//this print is 0
newdictionaries.forEach({ (postId, value) in
Database.database().fetchPost(withUID: user, postId: postId, completion: { (post) in
buyerPosts.append(post)
if buyerPosts.count == newdictionaries.count{
completion(buyerPosts)
}
})
})
}) { (err) in
print("Failed to fetch posts for buyers:", err)
cancel?(err)
}
}
尝试的答案:
let g = DispatchGroup() //// 1
for i in keys{
g.enter() //// 2
let newref = Database.database().reference().child("posts").child(user).child(search).child("purchases").child(i).child("purchaser")
print("now")
newref.observeSingleEvent(of: .value, with: { (snapshot)
newdictionaries[i] = snapshot.value as? String
print("print new dictionaries-->", newdictionaries)
// complete here
Database.database().fetchPost(withUID: user, postId: newdictionaries[i]!, completion: { (post) in
buyerPosts.append(post)
g.leave() //////// 3
})
})
}
g.notify(queue: DispatchQueue.main) {
print("finished!!!")
completion(buyerPosts)
}
您需要一个调度组并嵌套调用
let g = DispatchGroup() //// 1
for i in keys{
g.enter() //// 2
let newref = Database.database().reference().child("posts").child(user).child(search).child("purchases").child(i).child("purchaser")
newref.observeSingleEvent(of: .value, with: { (snapshot)
newdictionaries[i] = snapshot.value as? String
// complete here
Database.database().fetchPost(withUID: user, postId: postId, completion: { (post) in
buyerPosts.append(post)
g.leave() //////// 3
})
})
}
/// 4
g.notfiy(queue.main) {
completion(buyerPosts)
}