如何将一个实体映射到不同的 table

How to map one entity to different table

还有我的classTableOne.java:

@Table(name = "table_one")
@EntityListeners(AuditingEntityListener.class)
public class TableOne {
    @Id
    @GeneratedValue(generator = "UUID")
    @GenericGenerator(
            name = "UUID",
            strategy = "org.hibernate.id.UUIDGenerator")
    @Column(name = "id", unique = true, nullable = false, updatable = false)
    private String id;

    @CreatedDate
    @Column(name = "created", nullable = false, updatable = false)
    private LocalDateTime created;

    @LastModifiedDate
    @Column(name = "modified", nullable = false)
    private LocalDateTime modified;

    @Column(name = "status_desc")
    private String statusDesc;

    @OneToOne(cascade = CascadeType.ALL)
    @JoinColumn(table = "callers")
    private Party caller;

    @OneToOne(cascade = CascadeType.ALL)
    @JoinColumn(table = "callee")
    private Party callee;

    ...getter/setter
}

还有Part.java:

@Entity
public class Party {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id", unique = true, nullable = false, updatable = false)
    private long id;

    @Column(name = "desc")
    private String desc;

    @Column(name = "ip")
    private String ip;

    @Column(name = "port")
    private int port;
}

下面的字段:caller,callee inside TableOne.java包含相同的字段(id,desc,port,ip),所以我想把它们分成两份不同的表。例如在 calleecaller 表中。 我该怎么做?

您可以为此使用两个实体。只需从 Party 中删除 @Entity 注释并使用 @MappedSuperclass 对其进行注释。然后你可以创建两个实体:

@Entity
@Table(name = "caller")
public class Caller extends Party

@Entity
@Table(name = "callee")
public class Callee extends Party

两者将具有相同的字段,但将映射到两个不同的表。