检查日期时间列是否为空
Check if datetime column is empty
我想检查内部函数,比如日期时间列是否为空,请执行某些操作。
我的样本 df:
date_dogovor date_pogash date_pogash_posle_prodl
0 2019-03-07 2020-03-06 NaT
1 2019-02-27 2020-02-05 NaT
2 2011-10-14 2016-10-13 2019-10-13
3 2019-03-28 2020-03-06 NaT
4 2019-04-17 2020-04-06 NaT
我的函数:
def term(date_contract , date_paymnt, date_paymnt_aftr_prlngtn):
if date_paymnt_aftr_prlngtn is None:
return date_paymnt - date_contract
else:
return date_paymnt_aftr_prlngtn - date_contract
正在将函数应用于 df:
df['term'] = df.apply(lambda x: term(x['date_dogovor'], x['date_pogash'], x['date_pogash_posle_prodl']), axis=1 )
结果错误:
df['term']
0 NaT
1 NaT
2 NaT
3 NaT
4 NaT
...
115337 NaT
115338 NaT
115339 2921 days
115340 NaT
115341 NaT
Name: term, Length: 115342, dtype: timedelta64[ns]
如何正确检查日期时间列是否为空?
这里是 better/faster 使用 numpy.where
with Series.isna
:
df['term'] = np.where(df['date_pogash_posle_prodl'].isna(),
df['date_pogash'] - df['date_dogovor'],
df['date_dogovor'] - df['date_dogovor'])
您的函数应更改为 pandas.isna
:
def term(date_contract , date_paymnt, date_paymnt_aftr_prlngtn):
if pd.isna(date_paymnt_aftr_prlngtn):
return date_paymnt - date_contract
else:
return date_paymnt_aftr_prlngtn - date_contract
我想检查内部函数,比如日期时间列是否为空,请执行某些操作。 我的样本 df:
date_dogovor date_pogash date_pogash_posle_prodl
0 2019-03-07 2020-03-06 NaT
1 2019-02-27 2020-02-05 NaT
2 2011-10-14 2016-10-13 2019-10-13
3 2019-03-28 2020-03-06 NaT
4 2019-04-17 2020-04-06 NaT
我的函数:
def term(date_contract , date_paymnt, date_paymnt_aftr_prlngtn):
if date_paymnt_aftr_prlngtn is None:
return date_paymnt - date_contract
else:
return date_paymnt_aftr_prlngtn - date_contract
正在将函数应用于 df:
df['term'] = df.apply(lambda x: term(x['date_dogovor'], x['date_pogash'], x['date_pogash_posle_prodl']), axis=1 )
结果错误:
df['term']
0 NaT
1 NaT
2 NaT
3 NaT
4 NaT
...
115337 NaT
115338 NaT
115339 2921 days
115340 NaT
115341 NaT
Name: term, Length: 115342, dtype: timedelta64[ns]
如何正确检查日期时间列是否为空?
这里是 better/faster 使用 numpy.where
with Series.isna
:
df['term'] = np.where(df['date_pogash_posle_prodl'].isna(),
df['date_pogash'] - df['date_dogovor'],
df['date_dogovor'] - df['date_dogovor'])
您的函数应更改为 pandas.isna
:
def term(date_contract , date_paymnt, date_paymnt_aftr_prlngtn):
if pd.isna(date_paymnt_aftr_prlngtn):
return date_paymnt - date_contract
else:
return date_paymnt_aftr_prlngtn - date_contract