Mysql 数据库别名过滤器

Question

SELECT *
     , t.BG as TY
     , IF (t.BG >= 15, 'Y', 'D') AS Toplam 
  FROM 
     ( SELECT Uzmanadid AS Uzman_Ad
            , Kurumid
            , SUM(Bireysel)
            , IF(Kurumid like '%L%',
                IF(SUM(Bireysel) > 20, 200, 10)
              , IF(SUM(Bireysel) > 90, 20, 15)
                ) AS BG
        FROM Tbl_pss2 
       GROUP 
          BY Uzman_Ad) as t

我想过滤它，其中 Toplam = 'Y' 但我做不到。我试过这个：

SELECT *,t.BG as TY, IF (t.BG >= 15, 'Y', 'D') AS Toplam FROM (SELECT
Uzmanadid AS Uzman_Ad, Kurumid, SUM(Bireysel), IF(Kurumid like '%L%',
IF(SUM(Bireysel) > 20, 200, 10), IF(SUM(Bireysel) > 90, 20, 15)) AS BG
FROM Tbl_pss2 WHERE Toplam = 'Y' GROUP BY Uzman_Ad) as t

但是没有用。如果我尝试使用已经存在的列名（exp. Where Uzmanid = 'Alex'）过滤它，它就可以工作。但是其他代码不起作用，因为它只是别名还不存在。

那么我该如何过滤这个

Answer 1

列 Toplam 的值为：

IF (t.BG >= 15, 'Y', 'D')

所以条件：

Toplam = 'Y'

是 TRUE 当:

t.BG >= 15

所以你可以这样过滤：

WHERE t.BG >= 15

Mysql 数据库别名过滤器

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