使用 vba 发送 Post 请求,将当前 excel sheet 作为多部分表单数据

Send a Post request with the current excel sheet as multi-part form data using vba

我正在尝试将当前工作 excel sheet 发送到 api 接受内容类型:"multipart-form"。 我需要帮助来形成 vba 中的请求。 以下是我的做法:

Sub sendInternalDataToAPI(myCSVFileName As String)
    Dim data As Worksheet
    Dim boundary As String
    Dim filename As String


    boundary = "--------------------------784780577729000449617522"
    filename = "data"
    Set data = ActiveWorkbook.Sheets("DATA")
    'Set payload = preparePayload(data)
    Url = "http://localhost:8080/load"
    Set objHTTP = CreateObject("Microsoft.XMLHTTP")

    With objHTTP
    .Open "POST", Url, False
    .setRequestHeader "User-Agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0)"
    .setRequestHeader "Content-type", "multipart/form-data;boundary=" & boundary
    .send (preparePayload(data, boundary, myCSVFileName))
    strResponseStatus = .StatusText
    strResponse = .ResponseText
    allResponseHeader = .GetAllResponseHeaders
    End With
    Debug.Print strResponseStatus
    Debug.Print allResponseHeader
    Debug.Print strResponse
End Sub

Function preparePayload(data As Worksheet, boundary As String, filename As String) As String

    Debug.Print boundary & vbCrLf & _
    "Content-Disposition: form-data; name=""data""; filename=""" & filename & """" & vbCrLf & _
    "Content-Type: application/vnd.openxmlformats-officedocument.spreadsheetml.sheet" & vbCrLf & _
    data & vbCrLf & _
    boundary & "--"

    preparePayload = boundary & vbCrLf & _
    "Content-Disposition: form-data; name=""data""; filename=""" & filename & """" & vbCrLf & _
    "Content-Type: application/vnd.openxmlformats-officedocument.spreadsheetml.sheet" & vbCrLf & _
     data & vbCrLf & _
     boundary & "--"
End Function

执行时出现以下错误:

VBA Error: 438: Object doesn't support this property or method

表单正文中的变量 "data" 导致错误。我不确定我错过了什么! 而且,我从邮递员那里得到了请求正文中的内容类型,它执行得很好! 我是 vba 的新手,非常感谢任何帮助。

谢谢!

更新: 来自邮递员控制台的邮递员请求是:

Request ---
POST <url>/load HTTP/1.1
User-Agent: PostmanRuntime/7.22.0
Accept: */*
Cache-Control: no-cache
Postman-Token: d3a4355f-548a-4b10-b8b7-53c62772cc4a
Host: localhost:8080
Content-Type: multipart/form-data; boundary=--------------------------360126624207643168890089
Accept-Encoding: gzip, deflate, br
Content-Length: 352982
Connection: keep-alive
----------------------------360126624207643168890089
Content-Disposition: form-data; name="data"; filename="test-excel.xlsx"

<test-excel.xlsx>
----------------------------360126624207643168890089--


Response---

HTTP/1.1 200 OK
Date: Tue, 03 Mar 2020 13:41:17 GMT
Content-Type: application/json
X-Content-Type-Options: nosniff
X-XSS-Protection: 1; mode=block
Cache-Control: no-cache, no-store, max-age=0, must-revalidate
Pragma: no-cache
Expires: 0
X-Frame-Options: DENY
Transfer-Encoding: chunked

response Body fromt the server--
{"data":true}

如何仅使用请求正文中的文件名而不使用内容?

我认为问题在于您正在尝试将 "convert" Worksheet 变量 "data" 转换为 String 在您的 preparePayload 函数 中。

我不确定您使用的 API "prepare" 需要什么,如果它是工作表本身的名称,您可以使用 .Name 方法获取它,如果是其他东西,您需要确保将其正确转换为字符串,或者确保它可以隐式转换。

终于搞定了!

正如@TimWilliams 在评论中提到的,基本上我必须: 1.先从excel保存文件 2. 将其作为字符串读回 excel 3.转换成Bytes然后通过http

发送

这个 post 也帮了大忙:google.com/search?q=vba+post+excel+file+site:whosebug.com

此外,如果有一种方法可以将 ActiveWorkbook.sheet("MY_SHEET") 直接发送到 api,那就太好了。 会继续探索!

谢谢@TimWilliams!