使用 UNION 获取日期范围之间的 SUM

Question

我想根据每个日期从多个 table 组中获取两个日期之间每个 table 的总和。我的代码只获取一个分数，而不是获取每个日期的所有分数的总和。

SELECT z.dates
   COALESCE(a.allscore) AS cricket_score,
   COALESCE(b.allscore) AS football_score
   FROM (
   SELECT dateby AS dates FROM cricket_table
   UNION
   SELECT dateby FROM football_table) AS z
   LEFT JOIN (SELECT dateby AS dates, SUM(score) AS allscore FROM cricket_table
            WHERE dateby BETWEEN '2020-01-01' AND '2020-03-03'
           GROUP BY dates) a USING (dates)
   LEFT JOIN (SELECT dateby AS dates, SUM(score) AS allscore FROM football_table
            WHERE dateby BETWEEN '2020-01-01' AND '2020-03-03'
           GROUP BY dates) b USING (dates)
GROUP BY z.dates

[带数据库结构的完整代码]

$sql = "
create table cricket_table  (player varchar(50), score int, dateby date);

create table football_table  (player varchar(50), score int, dateby date);

insert into cricket_table values
('Sohail',32, '2020-01-02'),
('Saleem',65, '2020-01-02'), 
('Hamid',76, '2020-01-02'),

('Sohail',33, '2020-05-02'),
('Saleem',44, '2020-05-02'),
('Hamid',22, '2020-05-02');

insert into football_table values 
('Sohail',1, '2020-01-02'),
('Saleem',2, '2020-01-02'),
('Hamid',3, '2020-01-02'),

('Sohail',6, '2020-05-02'),
('Saleem',7, '2020-05-02'),
('Hamid',8, '2020-05-02');
";

$result = $db->prepare($sql);
$result->execute();

$query = $db->prepare("SELECT z.dates
       COALESCE(a.allscore) AS cricket_score,
       COALESCE(b.allscore) AS football_score
       FROM (
   SELECT dateby AS dates FROM cricket_table
   UNION
   SELECT dateby FROM football_table) AS z
   LEFT JOIN (SELECT dateby AS dates, SUM(score) AS allscore FROM cricket_table
                WHERE dateby BETWEEN '2020-01-01' AND '2020-03-03'
               GROUP BY dates) a USING (dates)
  LEFT JOIN (SELECT dateby AS dates, SUM(score) AS allscore FROM football_table
                WHERE dateby BETWEEN '2020-01-01' AND '2020-03-03'
               GROUP BY dates) b USING (dates)
    GROUP BY dates
");
$query->execute();
echo '<table><tr><th>Player Name</th><th>Cricket</th><th>Football</th></tr>';
while($row = $query->fetch(PDO:: FETCH_ASSOC) ) {
    echo '<tr>
        <td>'.$row['player'].'</td>
        <td>'.$row['cricket_score'].'</td>
        <td>'.$row['football_score'].'</td>
     </tr>';
}
echo '</table>';

(https://pastebin.com/prvsd1X8)

Answer 1

您有一些小问题：

第一行 z.dates 后缺少逗号
当 allscore 为 NULL

COALESCE

您在子查询 (BETWEEN '2020-01-01' AND '2020-03-03') 中的日期范围不包括 cricket_table 和 football_table
外部查询不需要 GROUP BY。

因此您的查询应如下所示：

SELECT z.dates,
       COALESCE(a.allscore, 0) AS cricket_score,
       COALESCE(b.allscore, 0) AS football_score
FROM (
  SELECT dateby AS dates FROM cricket_table
  UNION
  SELECT dateby FROM football_table
) AS z
LEFT JOIN (SELECT dateby AS dates, SUM(score) AS allscore 
           FROM cricket_table
           WHERE dateby BETWEEN '2020-01-01' AND '2020-05-03'
           GROUP BY dates
           ) a USING (dates)
LEFT JOIN (SELECT dateby AS dates, SUM(score) AS allscore 
           FROM football_table
           WHERE dateby BETWEEN '2020-01-01' AND '2020-05-03'
           GROUP BY dates
           ) b USING (dates)

示例数据的输出：

dates       cricket_score   football_score
2020-01-02  173             6
2020-05-02  99              21

Demo on dbfiddle

Answer 2

所以你想要日期方面 cricket_score 和 football_score 检查以下查询是否符合您的期望

SELECT dateby, SUM(cricket_score) AS cricket_score, SUM(football_score) AS football_score
FROM (

SELECT c.dateby, c.score AS cricket_score, 0 AS football_score 
FROM cricket_table AS c 
WHERE c.dateby BETWEEN '2020-01-01' AND '2020-07-05' 

UNION

SELECT f.dateby, 0 AS cricket_score, f.score AS football_score 
FROM football_table AS f 
WHERE f.dateby BETWEEN '2020-01-01' AND '2020-07-05'

) AS temp GROUP BY dateby

简单易行的方法

演示：http://sqlfiddle.com/#!18/fc606/15

输出

dateby       cricket_score   football_score
2020-01-02    173             6
2020-05-02    99              21

使用 UNION 获取日期范围之间的 SUM

Get SUM between daterange using UNION

php

mysql

union