在 JSON 个对象上加入 table

Joining table on JSON object

我有 table A,其中有 JSON 列 f,内容如下:

[{"name": "abc", "id": "1"}, {"name": "abcd", "id": "2"}, {"name": "abcde", "id": "3"} ]

我想加入另一个 table B on id inside JSON object described above 但也从 [=34= 获取 属性 name ] 对象。

我设法创建了以下查询:

WITH sample_data_array(arr) AS (
   SELECT f FROM A
), sample_data_elements(elem) AS (
   SELECT json_array_elements(arr) FROM sample_data_array
)
SELECT CAST(elem->>'id' AS int) AS id, elem->'name' AS name FROM sample_data_elements

returns 以下结果:

id, name
1, "abc"
2, "abcd"
3, "abcde"

示例数据来自 table B:

id, title, slug  
1, "title 1", "title-1"
2, "title 2", "title-2"
3, "title 3", "title-3"

如何将此结果与 table B 相结合,并从所述 table 添加更多数据(列)?

预期结果:

id, name, title, slug
1, "abc", "title 1", "title-1"
2, "abcd", "title 2", "title-2"
3, "abcde", "title 3", "title-3"

Click: demo:db<>fiddle

SELECT
    b.id,
    elems ->> 'name' as name,           -- 3
    b.title
FROM
    a,
    json_array_elements(f) as elems     -- 1
JOIN
    b ON b.id = (elems ->> 'id')::int   -- 2
  1. 使用 json_array_elements()
  2. 从 json 数组中取出元素
  3. 现在您可以加入 JSON 属性(在本例中:id 属性作为 text 并将其转换为 int 值)
  4. 加入后从 b 和数组元素(如 name)中获取所有相关值