根据另一个查询集的结果过滤一个查询集

Question

所以我有一个名为 post 的模型，它的一个字段是用户模型的外键，我还有另一个名为订阅的模型，它有 2 个外键，一个指向用户，另一个指向用户引用另一个帐户，我想过滤 post 查询集以仅显示来自存在订阅对象的人的 posts，用户订阅了 post 的创建者。我的模型如下所示：

class post(models.Model):
    creator = models.ForeignKey(Account,blank=False,null=False,on_delete=models.CASCADE)
    ...

class subscriptions(models.Model):
    subscriber = models.ForeignKey(Account,blank=False,null=False,on_delete = models.CASCADE, related_name='subscriber')
    subscribed_to = models.ForeignKey(Account,blank=False,null=False,on_delete = models.CASCADE, related_name='subscribed_to')

我尝试在视图中这样做

posts = post.objects.filter(creator__in = request.user.subscribed_to)

但它 return 没什么

这是我的账户模型：

class Account(AbstractBaseUser):
    email = models.EmailField(verbose_name='email', max_length=60, unique=True)
    username = models.CharField(max_length=30, unique=True)
    first_name = models.CharField(max_length=30)
    last_name = models.CharField(max_length=30)
    addresse = models.CharField(max_length=60)
    city = models.CharField(max_length=50)
    party_count = models.IntegerField(default=0)
    verified = models.BooleanField(default=False)
    profil_pic = models.ImageField(upload_to='profil_pics/',blank=True)
    birthday = models.DateField(default=date.today())
    date_joined = models.DateTimeField(verbose_name='date_joined', auto_now_add=True)
    last_login = models.DateTimeField(verbose_name='last_login', auto_now=True)
    is_admin = models.BooleanField(default=False)
    is_active = models.BooleanField(default=True)
    is_staff = models.BooleanField(default=False)
    is_superuser = models.BooleanField(default=False)

    USERNAME_FIELD = 'username'
    REQUIRED_FIELDS = ['email','first_name','last_name','addresse','birthday','city']

    objects = MyAccountManager()

    def __str__(self):
        return self.username

    def has_perm(self, perm, obj=None):
        return self.is_admin

    def has_module_perms(self,app_label):
        return True

Answer 1

经过一些研究后，我最终找到了一些导致以下结果的信息：

subs = subscriptions.objects.filter(subscriber=request.user).values_list('subscribed_to')
posts = post.objects.filter(creator__in = subs

Answer 2

一次查询即可解决。

Post.objects.filter(creator__subscribed_to__subscriber=request.user)

根据另一个查询集的结果过滤一个查询集

filtering a queryset based on the results of anoter one

python

django

django-queryset