JQ转CSV问题
JQ to CSV issues
我以前在这里得到了一些关于 jq 到 csv 问题的帮助。我 运行 遇到一个问题,其中一些 json 文件有一些额外的值会破坏 jq 命令
这是 json 数据。修复部分破坏了 jq 命令
[
{
"Name": "John Doe",
"Car": [
"Car1",
"Car2"
],
"Location": "Texas",
"Repairs: {
"RepairLocations": {
"RepairsCompleted":[
"Fix1",
"Fix2"
]
}
}
},
{
"Name": "Jane Roe",
"Car": "Car1",
"Location": [
"Illinois",
"Kansas"
]
}
]
这是命令
def expand($keys):
. as $in
| reduce $keys[] as $k ( [{}];
map(. + {
($k): ($in[$k] | if type == "array" then .[] else . end)
})
) | .[];
(.[0] | keys_unsorted) as $h
| $h, (.[] | expand($h) | [.[$h[]]]) | @csv
这是我想要得到的最终结果。此数据不是实际数据。
Name,Car,Location,Repairs:RepairLocation
John Doe,Car1,Texas,RepairsCompleted:Fix1
John Doe,Car1,Texas,RepairsCompleted:Fix2
John Doe,Car2,Texas,RepairsCompleted:Fix1
John Doe,Car2,Texas,RepairsCompleted:Fix2
Jane Roe,Car1,Illinois,
Jane Roe,Car1,Kansas,
对此有任何建议都很好。我正在努力弄清楚 jq
可以使用 的一个答案中所示的相同技术获得一个简单的解决方案。唯一的区别是在 "Repairs" 键不存在的情况下满足您的要求:
["Name", "Car", "Location", "Repairs:RepairLocation"],
(.[]
| [.Name]
+ (.Car|..|scalars|[.])
+ (.Location|..|scalars|[.])
+ (.Repairs|..|scalars
| [if . == null then . else "RepairsCompleted:\(.)" end]) )
| @csv
使用辅助函数避免重复
def s: .. | scalars | [.];
["Name", "Car", "Location", "Repairs:RepairLocation"],
(.[]
| [.Name]
+ (.Car|s)
+ (.Location|s)
+ (.Repairs|s|map(if . == null then . else "RepairsCompleted:\(.)" end)))
| @csv
我以前在这里得到了一些关于 jq 到 csv 问题的帮助。我 运行 遇到一个问题,其中一些 json 文件有一些额外的值会破坏 jq 命令
这是 json 数据。修复部分破坏了 jq 命令
[
{
"Name": "John Doe",
"Car": [
"Car1",
"Car2"
],
"Location": "Texas",
"Repairs: {
"RepairLocations": {
"RepairsCompleted":[
"Fix1",
"Fix2"
]
}
}
},
{
"Name": "Jane Roe",
"Car": "Car1",
"Location": [
"Illinois",
"Kansas"
]
}
]
这是命令
def expand($keys):
. as $in
| reduce $keys[] as $k ( [{}];
map(. + {
($k): ($in[$k] | if type == "array" then .[] else . end)
})
) | .[];
(.[0] | keys_unsorted) as $h
| $h, (.[] | expand($h) | [.[$h[]]]) | @csv
这是我想要得到的最终结果。此数据不是实际数据。
Name,Car,Location,Repairs:RepairLocation
John Doe,Car1,Texas,RepairsCompleted:Fix1
John Doe,Car1,Texas,RepairsCompleted:Fix2
John Doe,Car2,Texas,RepairsCompleted:Fix1
John Doe,Car2,Texas,RepairsCompleted:Fix2
Jane Roe,Car1,Illinois,
Jane Roe,Car1,Kansas,
对此有任何建议都很好。我正在努力弄清楚 jq
可以使用
["Name", "Car", "Location", "Repairs:RepairLocation"],
(.[]
| [.Name]
+ (.Car|..|scalars|[.])
+ (.Location|..|scalars|[.])
+ (.Repairs|..|scalars
| [if . == null then . else "RepairsCompleted:\(.)" end]) )
| @csv
使用辅助函数避免重复
def s: .. | scalars | [.];
["Name", "Car", "Location", "Repairs:RepairLocation"],
(.[]
| [.Name]
+ (.Car|s)
+ (.Location|s)
+ (.Repairs|s|map(if . == null then . else "RepairsCompleted:\(.)" end)))
| @csv