CTE表达式后得到具体结果

Get specific result after CTE expression

我有这样的 CTE:

DECLARE @LastDesigns AS TABLE
(
    [LegacyKey]       INT
    , [DesignKey]     INT
    , [Folio]         INT
    , [StatusKey]     INT
    , [DesignGroupId] UNIQUEIDENTIFIER
)

INSERT INTO @LastDesigns
    SELECT
        [P].[LegacyKey]
        , [D].[DesignKey]
        , [D].[Folio]
        , [D].[StatusKey]
        , [D].[DesignGroupId]
    FROM EbCorp.dbo.Project AS P
    INNER JOIN EbCorp.dbo.DesignGroup AS DG ON P.ProjectKey = DG.ProjectKey
    INNER JOIN EbCorp.dbo.Design AS D ON DG.DesignGroupId = D.DesignGroupId
    WHERE [D].[IsDeleted] = 0
        AND [ParentDesignGroupId] IS NULL;

WITH CTE2 (
    [LegacyKey]
    , [DesignKey]
    , [Folio]
    , [StatusKey]
    , [DesignGroupId]
    , [RN]
) AS (
    SELECT
        [LegacyKey]
        , [DesignKey]
        , [Folio]
        , [StatusKey]
        , [DesignGroupId]
        , ROW_NUMBER() OVER (PARTITION BY [LegacyKey], [DesignGroupId] ORDER BY [DesignKey] DESC) AS [RN]
    FROM @LastDesigns
)
SELECT
    [LegacyKey]
    , [DesignKey]
    , [Folio]
    , [StatusKey]
    , [DesignGroupId]
FROM CTE2
WHERE [RN] = 1;

此查询returns信息如下:

+-----------+-----------+-------+-----------+--------------------------------------+
| LegacyKey | DesignKey | Folio | StatusKey |            DesignGroupId             |
+-----------+-----------+-------+-----------+--------------------------------------+
|     18233 |      7540 |  5465 |        67 | 25687D54-B109-451B-9386-DD21C24ABBA9 |
|     18233 |      7543 |  5464 |        67 | 25687D54-B109-451B-9386-DD21C24ABBA9 |
|     18233 |      5229 |  4104 |       111 | 7E9F6DC9-6D1F-40DA-9D84-FE4D969A4289 |
|     18234 |      3920 |  2792 |        67 | 44D2DAFB-1880-4B93-AD04-2336B43E5BCA |
|     18235 |      7381 |  5306 |        67 | 7ADF74D6-A915-4882-9AC4-80FD801E9570 |
+-----------+-----------+-------+-----------+--------------------------------------+

我们只关注 2 列:LegacyKeyStatusKey

如您所见,前三行具有相同的 LegacyKey,但其中一行具有不同的 StatusKey。我的目标是检测具有相同 LegacyKey 但不同 StatusKey 的 LegacyKey 号码。 CTE 表达式后如何实现?

My goal is to detect LegacyKey numbers who have same LegacyKey but different StatusKey.

您可以使用聚合和 having 子句:

with q as (
      <your query here>
     )
select LegacyKey
from q
group by LegacyKey
having min(StatusKey) <> max(StatusKey);