CTE表达式后得到具体结果
Get specific result after CTE expression
我有这样的 CTE:
DECLARE @LastDesigns AS TABLE
(
[LegacyKey] INT
, [DesignKey] INT
, [Folio] INT
, [StatusKey] INT
, [DesignGroupId] UNIQUEIDENTIFIER
)
INSERT INTO @LastDesigns
SELECT
[P].[LegacyKey]
, [D].[DesignKey]
, [D].[Folio]
, [D].[StatusKey]
, [D].[DesignGroupId]
FROM EbCorp.dbo.Project AS P
INNER JOIN EbCorp.dbo.DesignGroup AS DG ON P.ProjectKey = DG.ProjectKey
INNER JOIN EbCorp.dbo.Design AS D ON DG.DesignGroupId = D.DesignGroupId
WHERE [D].[IsDeleted] = 0
AND [ParentDesignGroupId] IS NULL;
WITH CTE2 (
[LegacyKey]
, [DesignKey]
, [Folio]
, [StatusKey]
, [DesignGroupId]
, [RN]
) AS (
SELECT
[LegacyKey]
, [DesignKey]
, [Folio]
, [StatusKey]
, [DesignGroupId]
, ROW_NUMBER() OVER (PARTITION BY [LegacyKey], [DesignGroupId] ORDER BY [DesignKey] DESC) AS [RN]
FROM @LastDesigns
)
SELECT
[LegacyKey]
, [DesignKey]
, [Folio]
, [StatusKey]
, [DesignGroupId]
FROM CTE2
WHERE [RN] = 1;
此查询returns信息如下:
+-----------+-----------+-------+-----------+--------------------------------------+
| LegacyKey | DesignKey | Folio | StatusKey | DesignGroupId |
+-----------+-----------+-------+-----------+--------------------------------------+
| 18233 | 7540 | 5465 | 67 | 25687D54-B109-451B-9386-DD21C24ABBA9 |
| 18233 | 7543 | 5464 | 67 | 25687D54-B109-451B-9386-DD21C24ABBA9 |
| 18233 | 5229 | 4104 | 111 | 7E9F6DC9-6D1F-40DA-9D84-FE4D969A4289 |
| 18234 | 3920 | 2792 | 67 | 44D2DAFB-1880-4B93-AD04-2336B43E5BCA |
| 18235 | 7381 | 5306 | 67 | 7ADF74D6-A915-4882-9AC4-80FD801E9570 |
+-----------+-----------+-------+-----------+--------------------------------------+
我们只关注 2 列:LegacyKey
和 StatusKey
如您所见,前三行具有相同的 LegacyKey
,但其中一行具有不同的 StatusKey
。我的目标是检测具有相同 LegacyKey
但不同 StatusKey
的 LegacyKey 号码。 CTE
表达式后如何实现?
My goal is to detect LegacyKey numbers who have same LegacyKey but different StatusKey.
您可以使用聚合和 having
子句:
with q as (
<your query here>
)
select LegacyKey
from q
group by LegacyKey
having min(StatusKey) <> max(StatusKey);
我有这样的 CTE:
DECLARE @LastDesigns AS TABLE
(
[LegacyKey] INT
, [DesignKey] INT
, [Folio] INT
, [StatusKey] INT
, [DesignGroupId] UNIQUEIDENTIFIER
)
INSERT INTO @LastDesigns
SELECT
[P].[LegacyKey]
, [D].[DesignKey]
, [D].[Folio]
, [D].[StatusKey]
, [D].[DesignGroupId]
FROM EbCorp.dbo.Project AS P
INNER JOIN EbCorp.dbo.DesignGroup AS DG ON P.ProjectKey = DG.ProjectKey
INNER JOIN EbCorp.dbo.Design AS D ON DG.DesignGroupId = D.DesignGroupId
WHERE [D].[IsDeleted] = 0
AND [ParentDesignGroupId] IS NULL;
WITH CTE2 (
[LegacyKey]
, [DesignKey]
, [Folio]
, [StatusKey]
, [DesignGroupId]
, [RN]
) AS (
SELECT
[LegacyKey]
, [DesignKey]
, [Folio]
, [StatusKey]
, [DesignGroupId]
, ROW_NUMBER() OVER (PARTITION BY [LegacyKey], [DesignGroupId] ORDER BY [DesignKey] DESC) AS [RN]
FROM @LastDesigns
)
SELECT
[LegacyKey]
, [DesignKey]
, [Folio]
, [StatusKey]
, [DesignGroupId]
FROM CTE2
WHERE [RN] = 1;
此查询returns信息如下:
+-----------+-----------+-------+-----------+--------------------------------------+
| LegacyKey | DesignKey | Folio | StatusKey | DesignGroupId |
+-----------+-----------+-------+-----------+--------------------------------------+
| 18233 | 7540 | 5465 | 67 | 25687D54-B109-451B-9386-DD21C24ABBA9 |
| 18233 | 7543 | 5464 | 67 | 25687D54-B109-451B-9386-DD21C24ABBA9 |
| 18233 | 5229 | 4104 | 111 | 7E9F6DC9-6D1F-40DA-9D84-FE4D969A4289 |
| 18234 | 3920 | 2792 | 67 | 44D2DAFB-1880-4B93-AD04-2336B43E5BCA |
| 18235 | 7381 | 5306 | 67 | 7ADF74D6-A915-4882-9AC4-80FD801E9570 |
+-----------+-----------+-------+-----------+--------------------------------------+
我们只关注 2 列:LegacyKey
和 StatusKey
如您所见,前三行具有相同的 LegacyKey
,但其中一行具有不同的 StatusKey
。我的目标是检测具有相同 LegacyKey
但不同 StatusKey
的 LegacyKey 号码。 CTE
表达式后如何实现?
My goal is to detect LegacyKey numbers who have same LegacyKey but different StatusKey.
您可以使用聚合和 having
子句:
with q as (
<your query here>
)
select LegacyKey
from q
group by LegacyKey
having min(StatusKey) <> max(StatusKey);