Pygame 碰撞检查错误

Question

我最近开始在 Pygame 制作 Atari Breakout，我遇到了一个奇怪的错误。每当球碰到球拍的左侧时，它会正常弹开，但当球碰到球拍的右侧时，它会飞过球拍。请帮助，因为我不知道如何解决它。

这是我的代码：

import pygame, random, math

pygame.init()

screen = pygame.display.set_mode((800,600))
pygame.display.set_caption('Atari Breakout')

player = pygame.image.load('player copy.png')
ball = pygame.image.load('poland.png')

ballx, bally = 400, 300
balldx, balldy = 2,2
def isCollision(x1,y1,x2,y2):
    distance = math.sqrt(math.pow(x1 - x2, 2) + math.pow(y1 - y2, 2))
    if distance <= 32:
        return True
    else:
        return False
running = True

while running:

    screen.fill((0,0,0))

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False

    pos = pygame.mouse.get_pos()
    if isCollision(ballx, bally, pos[0], 525):
        balldy *= -1
    if bally >= 0:
        balldy *= -1
    if bally <= 570:
        balldy *= -1
    if ballx <= 0:
        balldx *= -1
    if ballx >= 770:
        balldx *= -1

    ballx += balldx
    bally += balldy

    screen.blit(player, (pos[0], 525))
    screen.blit(ball, (ballx,bally))

    pygame.display.update()

Answer 1

实际上 isCollision 计算围绕球的矩形左上角和球拍左上角之间的 Euclidean distance。
播放器（桨）的形状是一个长方形，边很长，边很短。因此，碰撞算法根本不起作用。我建议使用 pygame.Rect 对象和 colliderect 来检测球与玩家之间的碰撞。例如：

def isCollision(x1,y1,x2,y2):
    ballRect = ball.get_rect(topleft = (x1, y1))
    playerRect = player.get_rect(topleft = (x2, y2))
    return ballRect.colliderect(playerRect)

while running:
    # [...]

    pos = pygame.mouse.get_pos()
    if isCollision(ballx, bally, pos[0], 525):
        balldy *= -1

Pygame 碰撞检查错误

Pygame collision check bug

python

pygame

collision-detection

python-3.x