如何计算python中字符串中的字符数?
how to count characters in a string in python?
我创建了一个函数来计算字符串中的字符数,代码如下:
def count_characters_in_string(mystring):
s=0
x=mystring
for i in x:
t=i.split()
s=s+len(t)
print("The number of characters in this string is:",s)
count_characters_in_string("Apple")
这就是它 returns:
此字符串中的字符数为:1
此字符串中的字符数为:2
此字符串中的字符数为:3
此字符串中的字符数为:4
这个字符串的字符数是:5
有没有办法只打印最后一行以便打印:
这个字符串的字符数是:5
你可以只使用:
len(mystring)
在您的代码中,要仅打印最后一行,您可以使用:
for i in x:
s += 1
print("The number of characters in this string is:",s)
在python中,字符串可以看作是一个列表,你可以只取它的长度
def count_characters_in_string(word):
return len(word)
使用这个:
def count_characters_in_string(input_string)
letter_count = 0
for char in input_string:
if char.isalpha():
letter_count += 1
print("The number of characters in this string is:", letter_count)
当你运行:
count_characters_in_string("Apple Banana")
它会输出:
"The number of characters in this string is: 11"
这应该有效。
def count_characters_in_string(mystring):
s=0
x=mystring
for i in x:
t=i.split()
s=s+len(t)
print("The number of characters in this string is:",s)
count_characters_in_string("Apple")
我创建了一个函数来计算字符串中的字符数,代码如下:
def count_characters_in_string(mystring):
s=0
x=mystring
for i in x:
t=i.split()
s=s+len(t)
print("The number of characters in this string is:",s)
count_characters_in_string("Apple")
这就是它 returns: 此字符串中的字符数为:1 此字符串中的字符数为:2 此字符串中的字符数为:3 此字符串中的字符数为:4 这个字符串的字符数是:5
有没有办法只打印最后一行以便打印:
这个字符串的字符数是:5
你可以只使用:
len(mystring)
在您的代码中,要仅打印最后一行,您可以使用:
for i in x:
s += 1
print("The number of characters in this string is:",s)
在python中,字符串可以看作是一个列表,你可以只取它的长度
def count_characters_in_string(word):
return len(word)
使用这个:
def count_characters_in_string(input_string)
letter_count = 0
for char in input_string:
if char.isalpha():
letter_count += 1
print("The number of characters in this string is:", letter_count)
当你运行:
count_characters_in_string("Apple Banana")
它会输出:
"The number of characters in this string is: 11"
这应该有效。
def count_characters_in_string(mystring):
s=0
x=mystring
for i in x:
t=i.split()
s=s+len(t)
print("The number of characters in this string is:",s)
count_characters_in_string("Apple")