使用 RSA 现有模数和指数 C# 加密

Question

我正在尝试使用来自服务器 API 的模数和指数来加密一些数据。我尝试了几种不同的方法，但没有取得任何进展。到目前为止，这就是我所拥有的。我省略了更多的模数。

static void Main(string[] args)
{
    RSAParameters result = new RSAParameters())

        Modulus = Convert.FromBase64String("MjMwMDM5MDYyODE5NDc3MTQwODE5MzM0MTM4NzgzNjUyNTQ1MTU5NzAxNTY5NjIyMTc4OTc1NzIwODUzNjQwODY2NjM3NTI4NDQ1NDYzODU5MzY0NDY4MjIzMjk0MTI3NTg4NjY5NTQ5NjkxOTgxNTIxOTMwMzEwMTg4Njg4MjMzNjUzOTYwNzkzMzkzNjQwMDEwNjk3MDA3ODA4MDc3NDM1MTc1ODcwMjk2NzQ2ODQzMjAyODgwNzgxNzYzNDcxNTY2OTc0NDQ2MjY2NDA2MTQxOTU1Nzk4MjQwOTMwMjIxNzA4NTkzNDk5NjQ0MDM0ODc3ODQzODYxOTgyOTAyOTYxMzI0NzkyODAzNjQ1Mzk2MTk0ODcyNz=");
        Exponent = Encoding.ASCII.GetBytes("10001");

    byte[] bytes = Encoding.ASCII.GetBytes("data");

    using (RSACryptoServiceProvider RSA = new RSACryptoServiceProvider())
    {
        RSA.ImportParameters(result);
        var encryptedData = RSA.Encrypt(bytes, true);
        Console.WriteLine(encryptedData);
    }
}

目前这让我遇到错误数据异常，我不确定为什么。 python我也试过，结果不对。如果需要，我愿意使用另一种语言。谢谢您的帮助！

Answer 1

编辑 1：

非常有趣但是

Convert.FromBase64String("MjMwMDM5MDYyODE5NDc3MTQwODE5MzM0MTM4NzgzNjUyNTQ1MTU5NzAxNTY5NjIyMTc4OTc1NzIwODUzNjQwODY2NjM3NTI4NDQ1NDYzODU5MzY0NDY4MjIzMjk0MTI3NTg4NjY5NTQ5NjkxOTgxNTIxOTMwMzEwMTg4Njg4MjMzNjUzOTYwNzkzMzkzNjQwMDEwNjk3MDA3ODA4MDc3NDM1MTc1ODcwMjk2NzQ2ODQzMjAyODgwNzgxNzYzNDcxNTY2OTc0NDQ2MjY2NDA2MTQxOTU1Nzk4MjQwOTMwMjIxNzA4NTkzNDk5NjQ0MDM0ODc3ODQzODYxOTgyOTAyOTYxMzI0NzkyODAzNjQ1Mzk2MTk0ODcyNz=");

因长度无效而失败。

https://www.base64decode.org/ 将此 base64 内容解码为

2300390628194771408193341387836525451597015696221789757208536408666375284454638593644682232941275886695496919815219303101886882336539607933936400106970078080774351758702967468432028807817634715669744462664061419557982409302217085934996440348778438619829029613247928036453961948727

起初我以为该站点给了我解码后的字节的十六进制表示形式。不幸的是，它只打印出一个字符串。

这意味着我们需要再应用一个转换（当我把答案放在这里时，我已经在我的代码中完成了这个，但没有说明应该如何在你的代码中完成）

这也是应该适用于您的代码：

static void Main(string[] args)
{
    RSAParameters result = new RSAParameters()
    {
        // If the following is working on your system:
        Modulus = HexStringToByteArray(Convert.FromBase64String("MjMwMDM5MDYyODE5NDc3MTQwODE5MzM0MTM4NzgzNjUyNTQ1MTU5NzAxNTY5NjIyMTc4OTc1NzIwODUzNjQwODY2NjM3NTI4NDQ1NDYzODU5MzY0NDY4MjIzMjk0MTI3NTg4NjY5NTQ5NjkxOTgxNTIxOTMwMzEwMTg4Njg4MjMzNjUzOTYwNzkzMzkzNjQwMDEwNjk3MDA3ODA4MDc3NDM1MTc1ODcwMjk2NzQ2ODQzMjAyODgwNzgxNzYzNDcxNTY2OTc0NDQ2MjY2NDA2MTQxOTU1Nzk4MjQwOTMwMjIxNzA4NTkzNDk5NjQ0MDM0ODc3ODQzODYxOTgyOTAyOTYxMzI0NzkyODAzNjQ1Mzk2MTk0ODcyNz=")),
        // And since it is not working on my environment:
        // Modulus = HexStringToByteArray("2300390628194771408193341387836525451597015696221789757208536408666375284454638593644682232941275886695496919815219303101886882336539607933936400106970078080774351758702967468432028807817634715669744462664061419557982409302217085934996440348778438619829029613247928036453961948727"),
        Exponent = HexStringToByteArray("010001")
    };

    byte[] bytes = Encoding.ASCII.GetBytes("data");

    using (RSACryptoServiceProvider RSA = new RSACryptoServiceProvider())
    {
        RSA.ImportParameters(result);
        var encryptedData = RSA.Encrypt(bytes, true);
        Console.WriteLine(encryptedData);
    }
}

原版POST:

问题在这里：

Exponent = Encoding.ASCII.GetBytes("10001");

这实际上是字节0x 01 00 01（3个字节）的十六进制表示

注意：对于您提供的输入，Convert.FromBase64String() 失败。这就是为什么人们对此感到困惑。它在我的本地也失败了，所以我使用了成功解码它的on-line decoder，

我使用这个解码值来重现模数。

    public static byte[] HexStringToByteArray(string hexString)
    {
        MemoryStream stream = new MemoryStream(hexString.Length / 2);
        for (int i = default(int); i < hexString.Length; i += 2)
        {
            stream.WriteByte(byte.Parse(hexString.Substring(i, 2), System.Globalization.NumberStyles.AllowHexSpecifier));
        }
        return stream.ToArray();
    }

然后；

Exponent = HexStringToByteArray("010001")

使用 RSA 现有模数和指数 C# 加密

Encrypting with RSA existing modulus and exponent C#

c#

rsa