如何从 r 中的列表中提取所有子列表？

Question

有很多接近的解决方案，但不幸的是我找不到正确的解决方案。我有如下列表列表。正如您所看到的，在他们的 up 列表下有 3 个子列表（01-2011、02-2011 和 01-2012）。但我只想获得名称为 (01-2011,02-2011 and 01-2012)

的列表

这是我的数据及其结构；

data<-list(structure(list(`01-2011` = structure(list(dmax = structure(list(
    m5 = 0.266, m10 = 0.532, m15 = 0.797, m30 = 1.092), .Names = c("m5", 
"m10", "m15", "m30"))), .Names = "dmax"), `01-2012` = structure(list(
    dmax = structure(list(m5 = 1.224, m10 = 2.395, m15 = 3.063, 
        m30 = 5.131), .Names = c("m5", "m10", "m15", "m30"))), .Names = "dmax")), .Names = c("01-2011", 
"01-2012")), structure(list(`02-2011` = structure(list(dmax = structure(list(
    m5 = 0.955, m10 = 1.683, m15 = 2.398, m30 = 4.539), .Names = c("m5", 
"m10", "m15", "m30"))), .Names = "dmax")), .Names = "02-2011"))


[[1]]
[[1]]$`01-2011`
[[1]]$`01-2011`$dmax
[[1]]$`01-2011`$dmax$m5
[1] 0.266

[[1]]$`01-2011`$dmax$m10
[1] 0.532

[[1]]$`01-2011`$dmax$m15
[1] 0.797

[[1]]$`01-2011`$dmax$m30
[1] 1.092



[[1]]$`01-2012`
[[1]]$`01-2012`$dmax
[[1]]$`01-2012`$dmax$m5
[1] 1.224

[[1]]$`01-2012`$dmax$m10
[1] 2.395

[[1]]$`01-2012`$dmax$m15
[1] 3.063

[[1]]$`01-2012`$dmax$m30
[1] 5.131




[[2]]
[[2]]$`02-2011`
[[2]]$`02-2011`$dmax
[[2]]$`02-2011`$dmax$m5
[1] 0.955

[[2]]$`02-2011`$dmax$m10
[1] 1.683

[[2]]$`02-2011`$dmax$m15
[1] 2.398

[[2]]$`02-2011`$dmax$m30
[1] 4.539

我尝试了 lapply(data, "[[") 但这给出了一个错误。

这是所需的输出；

out<-structure(list(`01-2011` = structure(list(dmax = structure(list(
    m5 = 0.266, m10 = 0.532, m15 = 0.797, m30 = 1.092), .Names = c("m5", 
"m10", "m15", "m30"))), .Names = "dmax"), `01-2012` = structure(list(
    dmax = structure(list(m5 = 1.224, m10 = 2.395, m15 = 3.063, 
        m30 = 5.131), .Names = c("m5", "m10", "m15", "m30"))), .Names = "dmax"), 
    `02-2011` = structure(list(dmax = structure(list(m5 = 0.955, 
        m10 = 1.683, m15 = 2.398, m30 = 4.539), .Names = c("m5", 
    "m10", "m15", "m30"))), .Names = "dmax")), .Names = c("01-2011", 
"01-2012", "02-2011"))



$`01-2011`
$`01-2011`$dmax
$`01-2011`$dmax$m5
[1] 0.266

$`01-2011`$dmax$m10
[1] 0.532

$`01-2011`$dmax$m15
[1] 0.797

$`01-2011`$dmax$m30
[1] 1.092



$`01-2012`
$`01-2012`$dmax
$`01-2012`$dmax$m5
[1] 1.224

$`01-2012`$dmax$m10
[1] 2.395

$`01-2012`$dmax$m15
[1] 3.063

$`01-2012`$dmax$m30
[1] 5.131



$`02-2011`
$`02-2011`$dmax
$`02-2011`$dmax$m5
[1] 0.955

$`02-2011`$dmax$m10
[1] 1.683

$`02-2011`$dmax$m15
[1] 2.398

$`02-2011`$dmax$m30
[1] 4.539

Answer 1

你可以 unlist 与 recursive = FALSE:

res <- unlist(data, recursive = FALSE)

检查输出：

all.equal(out, res)

# [1] TRUE

Answer 2

我们也可以用flatten

library(purrr)
res <- flatten(data)
identical(out, res)
#[1] TRUE

如何从 r 中的列表中提取所有子列表？

How to extract all sublists from a list in r?

r

extract