对 URL 的存储引用

StorageReference to URL

我正在尝试按照 Firebase 的文档了解如何在应用程序中向用户显示来自 firebase 存储的图像。这是下面的文档:

// Reference to an image file in Firebase Storage
let reference = storageRef.child("images/stars.jpg")

// UIImageView in your ViewController
let imageView: UIImageView = self.imageView

// Placeholder image
let placeholderImage = UIImage(named: "placeholder.jpg")

// Load the image using SDWebImage
imageView.sd_setImage(with: reference, placeholderImage: placeholderImage)

我自己尝试这样做:

//get image url from deal
self.ref.child("deals").child("log").child(currentDealView).child("pictures").child(currentImageView).child("imageSelected").child("imageSelected").observeSingleEvent(of: .value) { (snapshot) in
    let imageUrlString = snapshot.value as! String
    let imageUrlUrl = URL(string: imageUrlString)

    print(imageUrlString)
    //prints "deals/log/dealNumber83/pictures/googleScreenshot/imageSelected"

    // Reference to an image file in Firebase Storage
    let reference = self.storageRef.child(imageUrlString)

    // UIImageView in your ViewController
    let viewPicImageView: UIImageView = self.viewPicImageView

    // Placeholder image
    let placeholderImage = UIImage(named: "placeholder.jpg")

    // Load the image using SDWebImage

    viewPicImageView.sd_setImage(with: reference, placeholderImage: placeholderImage)

但是在最后一行我在 "with: reference," 处出错说:"Cannot convert value of type 'StorageReference' to expected argument type 'URL?'" 我在网上找不到任何关于如何将 StorageReference 转换为 URL?谢谢。

你可以使用这个:

let Ref = Storage.storage().reference(forURL: imageUrlUrl)
Ref.getData(maxSize: 1 * 1024 * 1024) { data, error in
    if error != nil {
        print("Error: Image could not download!")
    } else {
        yourImageView.image = UIImage(data: data!)
    }
}

希望对您有所帮助...

或者,使用 FirebaseStorageSwift 测试版利用 Swift 结果类型。 (将 pod 'FirebaseStorageSwift' 添加到 Podfile。)

let Ref = Storage.storage().reference(forURL: imageUrlUrl)
Ref.getData(maxSize: 1 * 1024 * 1024) { result in
  switch result {
  case let .success(data):
    yourImageView.image = UIImage(data: data)
  case let .failure(error):
    print("Error: Image could not download! \(error)")
  }
}