较短的代码，因此用相同的值填充数组

Question

对于我的 "memory" 游戏，我使用 GridView 来显示 12 张牌。
一开始的牌都是一样的

在我找到的所有示例中，您会看到类似于此代码的内容，用于将图片 ID 添加到您的 ImageAdapter：

 private Integer[] mThumbIds = {     
        R.drawable.card_back, R.drawable.card_back,
        R.drawable.card_back, R.drawable.card_back,
        R.drawable.card_back, R.drawable.card_back,
        R.drawable.card_back, R.drawable.card_back,
        R.drawable.card_back, R.drawable.card_back,
        R.drawable.card_back, R.drawable.card_back
    };

有没有更短、更干净、更好的方法？像这样：

private Integer[] mThumbIds = new Integer[11];
Arrays.fill(mThumbIds, R.drawable.card_back);

完整 class:

import android.content.Context;
import android.view.View;
import android.view.ViewGroup;
import android.widget.BaseAdapter;
import android.widget.GridView;
import android.widget.ImageView;
import java.util.Arrays;

public class ImageAdapter extends BaseAdapter {
    private Context mContext;

    public ImageAdapter(Context c) {
        mContext = c;
    }

    public int getCount() {
        return mThumbIds.length;
    }

    public Object getItem(int position) {
        return null;
    }

    public long getItemId(int position) {
        return 0;
    }

    // create a new ImageView for each item referenced by the Adapter
    public View getView(int position, View convertView, ViewGroup parent) {
        ImageView imageView;
        if (convertView == null) {
            // if it's not recycled, initialize some attributes
            imageView = new ImageView(mContext);
            imageView.setLayoutParams(new GridView.LayoutParams(150, 150));
            imageView.setScaleType(ImageView.ScaleType.FIT_CENTER);
            imageView.setPadding(8, 8, 8, 8);
        } else {
            imageView = (ImageView) convertView;
        }

        imageView.setImageResource(mThumbIds[position]);
        return imageView;
    }

    // references to our images

    Integer[] mThumbIds = new Integer[11];
    Arrays.fill(mThumbIds, R.drawable.card_back);


       /*   R.drawable.card_back, R.drawable.card_back,
            R.drawable.card_back, R.drawable.card_back,
            R.drawable.card_back, R.drawable.card_back,
            R.drawable.card_back, R.drawable.card_back,
            R.drawable.card_back, R.drawable.card_back,
            R.drawable.card_back, R.drawable.card_back
    };*/

}

Answer 1

实际上，就是这样 - 您可以使用 java.util.Arrays#fill:

Arrays.fill(mThumbIds, R.drawable.card_back);

Answer 2

您可以使用 for 循环来初始化数组：

int arr[] = new int[12]; // 0 ... 11
for(int i = 0; i < arr.length; i++)
{
    arr[i] = R.drawable.card_back;
}

Answer 3

抱歉，低代表评论@Mureinik 的回答。通常为了保持我的构造函数干净并初始化对所有实例都相同的变量，我这样做：

private Integer[] mThumbIds = new Integer[11];
{
    Arrays.fill(mThumbIds, R.drawable.card_back);
}

此块在构造函数之前按实例调用。

较短的代码，因此用相同的值填充数组

Shorter code so fill arrays with same Value

java

arrays

android

gridview

image