其他元素没有返回正确的结果

Question

我创建了一个 select 语句，使用 php 将 return 结果转换为基于用户输入的 HTML。反馈是 return 根据输入字段匹配手动填充的字段 table 编辑的。 select 语句应该是 return 最高的 ID。表单将数据插入 'adoption' table。然后根据'adoption'table.table.table.'dogs'.table下面匹配的字段，结果return来自'dogs'的一行

<?php
$connect = mysqli_connect("localhost", "root", "", "ncdr_first", "3308");

$sql = "SELECT dogs.name, dogs.breed, dogs.age, dogs.sex, dogs.image, adoption.adoption_id 
        FROM dogs 
            INNER JOIN adoption ON dogs.adultRadio = adoption.adultRadio 
                AND dogs.child = adoption.child 
                AND dogs.petRadio = adoption.petRadio 
                AND dogs.pet = adoption.pet 
                AND dogs.activity = adoption.activity 
                AND dogs.home = adoption.home 
                AND dogs.environment = adoption.environment
        ORDER BY adoption.adoption_id DESC 
        LIMIT 0, 1";

$result = mysqli_query($connect, $sql);

?>

然后结果显示在页面 HTML 部分的 table 中。

<div class="table">
    <center><table id="feedback">
            <tr>
                <th>Name</th>
                <th>Breed</th>
                <th>Age</th>
                <th>Sex</th>
                <th>Image</th>
            </tr>
    <?php
    if($result->num_rows > 0){
        while($row = $result->fetch_assoc()){
    ?>
        <tr>
            <td><?php echo $row["name"];?></td>
            <td><?php echo $row["breed"];?></td>
            <td><?php echo $row["age"];?></td>
            <td><?php echo $row["sex"];?></td>  
            <td><img src="<?php echo $row["image"];?>"/></td>
        </tr>
    <?php
        }

    } else {
        echo "Unfortunately you have not been a match for any of our furry friends! Please try again soon.";
    }   
    ?>
    </center></table>


CREATE TABLE dogs (dog_id int, name varchar, breed varchar, age varchar, sex 
varchar, adultRadio varchar, child varchar, petRadio varchar, pet varchar, 
activity varchar, home varchar, environment varchar, image varchar ); 

CREATE TABLE adoption (adoption_id int, name varchar, address varchar, 
adultRadio varchar, child varchar, petRadio varchar, pet varchar, activity 
varchar, home varchar, environment varchar, image varchar );

但是，如果我向 'adoption' table 输入的数据与 'dogs' table 中的任何行都不匹配，它将 return 最后匹配的行而不是 else 中的语句。有人对如何解决这个问题有任何建议吗？

<?php
session_start();

//Check if user is logged in, if not redirect to login page
if(!isset($_SESSION["loggedin"]) || $_SESSION["loggedin"] !== true){
header("location: login.php");
exit;
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" 
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" lang="eng">
<head>
    <meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
    <meta name="view" content="width=device-width"/>
    <title>North Coast Dog Rescue Contact Page</title>
    <meta name="description" content="Responsive website for North Coast Dog 
 Rescue"/>
    <meta name="author" content="Chloe Leighton B00710338"/>
    <link rel="stylesheet" href="style.css"/>
<style type="text/css">
    .formContainer #adultNo:checked ~ .conditional, #petYes:checked ~ .conditional {
    clip: auto;
    height: auto;
    margin: 0;
    overflow: visible;
    position: static;
    width: auto;
    }

    .formContainer #adultNo:not(:checked) ~ .conditional, #petYes:not(:checked) ~ .conditional {
    border: 0;
    clip: rect(0 0 0 0);
    height: 1px;
    margin: -1px;
    overflow: hidden;
    padding: 0;
    position: absolute;
    width: 1px;
    }
</style>
</head>
<body>
    <div class="header">
        <div class="container">
            <div id="logo">
                <img src="images/logo.png" alt="logo"/>
            </div>
        <div class="nav">
            <ul>
                <li class="home"><a href="index.html">Home</a></li>
                <li class="about"><a href="aboutUs.html">About Us</a></li>
                <li class="dogs"><a href="dogs.html">Dogs for Adoption</a></li>
                <li class="current"><a href="adoptionForm.php">Online Adoption Form</a></li>
                <li class="contact"><a href="contactUs.html">Contact Us</a></li>
        <li class="login"><a href="login.php">Login</a></li>
            </ul>
            </div>
        </div>
    </div>
<form action="adoptionForm.php" method="post">

        <div class="formContainer">
    <h1>Adoption Form</h1>
    <p>Please fill in this form to be matched to a suitable dog.</p>
    <hr/>

            <label><b>Name</b></label>
            <input type="text" name="name"/>

            <label><b>Address</b></label>
            <input type="text" name="address"/>

            <label><b>Do you have an adult only home?</b></label><br />
            <input type="radio" name="adultRadio" id="adultYes" value="Yes" onclick="radio_check()"; /> Yes <br />
    <input type="radio" name="adultRadio" id="adultNo" value="No" onclick="radio_check()"; /> No <br />

    <div class="conditional">
        <label><b>If you don't have an adult only home, please select the age of any children: </b></label><br />
        <select id="child" size="0" name="child">
            <option value="" name=""></option>
            <option value="baby/toddler" name="baby/toddler">Baby/Toddler (0-4 years)</option>
            <option value="youngChild" name="youngChild">Small Child (5-12 years)</option>
            <option value="olderChild" name="olderChild">Older Child (13-18 years)</option>
        </select><br /> 
    </div>

    <label><b>Do you have any pets?</b></label><br/>
    <input type="radio" name="petRadio" id="petYes" value="Yes" onclick="radio_check()";/> Yes <br />
    <input type="radio" name="petRadio" id="petNo" value="No" onclick="radio_check()";/> No <br />

    <div class="conditional"> 
        <label><b>If you have a pet, please select the description that fits them best: </b></label><br />
        <select id="pet" name="pet"> 
            <option value="" name=""></option>
            <option value="youngDog" name="youngDog">Young, playful dog</option>
            <option value="oldDog" name="oldDog">Older, calm dog</option>
            <option value="cat" name="cat">Cat</option>
        </select>
    </div>

    <label><b>Please select which activity level fits you best: </b></label><br/>
    <select name="activity">
        <option value="notActive" name="notActive">Not very active</option>
        <option value="moderatelyActive" name="moderatelyActive">Moderately active</option>
        <option value="veryActive" name="veryActive">Very active</option>
    </select>

    <label><b>Please select how often you are at home: </b></label><br/>
    <select name="home">
        <option value="little" name="littleHome">At home very little</option>
        <option value="most" name="mostHome">At home most of the time</option>
        <option value="all" name="allHome">There is always someone at home</option>
    </select>



    <label><b>Please select which best describes your home environment: </b></label>
    <select name="environment">
        <option value="city" name="city">Busy city</option>
        <option value="suburbs" name="suburbs">Suburbs</option>
        <option value="rural" name="rural">Quiet and rural</option>
    </select>

            <button class="submit" type="submit">Submit Form</button>

        </div>

        <div class="loginContainer" style="background-color:#f1f1f1">
            <a href="logout.php"><button type="button" class="cancelbtn">Logout</button></a>
        </div>
    </form>

    <div class="footer">
        <p>North Coast Dog Rescue, Copyright &copy; 2020</p>
    </div>
</body>
    </html>

    <?php
    if($_SERVER["REQUEST_METHOD"] == "POST"){
    $name = $_POST['name'];
    $address = $_POST['address'];
    $adultRadio = $_POST['adultRadio'];
    $child = $_POST['child'];
    $petRadio = $_POST['petRadio'];
    $pet = $_POST['pet'];
    $activity = $_POST['activity'];
    $home = $_POST['home'];
    $environment = $_POST['environment'];
    $bool = true;

    //Connect to server and database
    $conn = mysqli_connect("localhost", "root", "", "ncdr_first", "3308");
    if (mysqli_connect_errno()) {
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }
    echo "Success: A proper connection to MySQL was made! <br>" ;
    echo "Host information: " . mysqli_get_host_info($conn) ;

    $query_ins = "INSERT INTO adoption (name, address, adultRadio, child, 
    petRadio, pet, activity, home, environment)
    VALUES ('$name', '$address', '$adultRadio', '$child', '$petRadio', 
    '$pet', '$activity', '$home', '$environment')";

    if($bool) {
    mysqli_query($conn, $query_ins);
    echo "<script>alert('Adoption form submitted successfully!');</script>";
    echo "<script>window.location.assign('feedback.php');</script>";
    }
    mysqli_free_result($result);
    mysqli_close($conn);
    }

    ?>

SQL query result

Answer 1

查看 SQL 代码，它将 return 匹配的最后一个 ID 而不是最后一个 ID。您可以 select 仅最后插入以下内容，

$sql = "SELECT dogs.name, dogs.breed, dogs.age, dogs.sex, dogs.image, adoption.adoption_id 
        FROM dogs 
            INNER JOIN adoption ON dogs.adultRadio = adoption.adultRadio 
                AND dogs.child = adoption.child 
                AND dogs.petRadio = adoption.petRadio 
                AND dogs.pet = adoption.pet 
                AND dogs.activity = adoption.activity 
                AND dogs.home = adoption.home 
                AND dogs.environment = adoption.environment
        WHERE adoption_id = (SELECT MAX(adoption_id) FROM adoption)";

其他元素没有返回正确的结果

Else element not returning the correct result

html

php

mysqli

join