如何将 "rect" 属性分配给 Pygame 中的 pygame.sprite.rect 矩形？

Question

这个问题以前有人问过，但是他们回答的代码不适用于我。

我想检查我的游戏中两个矩形何时发生碰撞，对于圆圈，我在圆圈后面放了一个矩形（它是黑色的）。

但是，当我运行时，我收到一条错误消息，指出矩形需要具有 rect 属性。

这是我的代码：

clock = pygame.time.Clock()

pygame.init()
change = False
screen = pygame.display.set_mode((400, 300))

done = False
x = 100
y = 30
bound = False
while not done:
    for event in pygame.event.get():


        if event.type == pygame.QUIT:
             done = True
        elif event.type == pygame.KEYDOWN and event.key == pygame.K_f:
             color = (255, 255, 255)
             pygame.draw.rect(screen, color, (110, 30, 60, 60))
             bound = True
        elif event.type == pygame.KEYDOWN and event.key == pygame.K_z:
             change = not change
    if bound:
        pressed = pygame.key.get_pressed()

        if pressed[pygame.K_DOWN] or pressed[pygame.K_s]:
            y += 5
        elif pressed[pygame.K_RIGHT] or pressed[pygame.K_d]:
            x += 5
        elif pressed[pygame.K_LEFT] or pressed[pygame.K_a]:
            x -= 5
        elif pressed[pygame.K_UP] or pressed[pygame.K_w]:
            y -= 5
        elif change:
            color2 = (0, 128, 86)
        else:
            color2 = (0, 128, 10)
        screen.fill((0, 0, 0))
        pygame.draw.rect(screen, color2, (x, y, 60, 60))
        #pygame.draw.rect(screen, (255, 255, 255), (150, 30, 10, 60))
        pygame.draw.rect(screen, (255, 255, 255), (x+ 65, y + 24, 20, 10))
    else:
        pressed = pygame.key.get_pressed()

        if pressed[pygame.K_DOWN] or pressed[pygame.K_s]:
            y += 5
        elif pressed[pygame.K_RIGHT] or pressed[pygame.K_d]:
            x += 5
        elif pressed[pygame.K_LEFT] or pressed[pygame.K_a]:
            x -= 5
        elif pressed[pygame.K_UP] or pressed[pygame.K_w]:
            y -= 5
        elif change:
            color2 = (0, 128, 86)
        else:
            color2 = (0, 128, 10)

        screen.fill((0, 0, 0))
        player = pygame.draw.rect(screen, color2, (x, y, 60, 60))
        back = pygame.draw.rect(screen, (0, 0, 0), (210, 210, 40, 40))
        gun1 = pygame.draw.circle(screen, (0, 0, 255), (250, 250), 40, 1)
        pygame.draw.rect(screen, (255, 255, 255), (240, 245, 20, 10))
    clock.tick(60)

    pygame.display.flip()

有人可以给我代码，将 rect 属性分配给我的矩形吗？

谢谢！

Answer 1

操作pygame.sprite.collide_rect(), pygame.sprite.spritecollide(), pygame.sprite.groupcollide() etc. are for the use with pygame.sprite.Sprite objects and pygame.sprite.Group个对象。
此操作使用 Sprite 对象的内部 .rect 属性来检测碰撞。

您既没有 Sprite 也没有 Group，但是您有 pygame.Rect 个对象。

验证是否为 2 pygame.Rect objects are colliding, you have to use pygame.Rect.colliderect()。例如：

player = pygame.draw.rect(screen, color2, (x, y, 60, 60))
back = pygame.draw.rect(screen, (0, 0, 0), (210, 210, 40, 40))
gun1 = pygame.draw.circle(screen, (0, 0, 255), (250, 250), 40, 1)

if player.colliderect(back):
    print("player collide back")
if player.colliderect(gun1):
    print("player collide gun1")

如何将 "rect" 属性分配给 Pygame 中的 pygame.sprite.rect 矩形？

How do you assign a "rect" attribute to a pygame.sprite.rect rectangle in Pygame?

python

error-handling

attributes

pygame

collision-detection