Select 范围内的所有年份，没有年份 table

Question

我选择了当前年份

SELECT EXTRACT(YEAR FROM NOW()) as value

我想打印从 1990 年到当年的所有年份的列表，而不必创建年份列表的 table，有没有办法做到这一点，或者我必须创建一个 table 做这个？

Answer 1

您可以为此使用递归查询：

with recursive cte as (
    select 1990 dt
    union all select dt + 1 from cte where dt < extract(year from now())
)
select dt from cte order by dt

Answer 2

select generate_series(1990, (extract(year from now()))::int) as value;

或

select value from generate_series(1990, (extract(year from now()))::int) as value;

Select all the years from a range without having a years table