删除常见的观察结果
Remove common observations
我有 2 个数据框
Map3 = pd.DataFrame({
"partner_country": ["France","France","France","France","France","France",
"Spain","Spain","Spain","Spain","Spain","Spain"
],
"my_network": ["Ireland","Austria",None,"Sweden","Italy",None , #France
"Ireland","Austria","Denmark","Sweden",None,"United Kingdom" #Spain
]})#Netherlands
Map4 = pd.DataFrame({
"partner_country": ["France","France","France","France","France","France",
"Spain","Spain","Spain","Spain","Spain","Spain"
],
"my_network": [None,None,None,None,"Italy",None , #France
None,"Austria",None,"Sweden",None,"United Kingdom" #Spain
]})#Netherlands
我想从 Map3 数据框中删除 Map3 和 Map4 中常见的所有观察结果。尝试了以下代码:
Map4[~(Map4['partner_country'].isin(Map3['partner_country'])Map4['my_network'].isin(Map3['my_network']]
一个简单的解决方案,因为您只有 2 列可能是:
common = (Map3.partner_country + Map3.my_network).isin(Map4.partner_country + Map4.my_network)
Map3 = Map3.loc[~common]
我有 2 个数据框
Map3 = pd.DataFrame({
"partner_country": ["France","France","France","France","France","France",
"Spain","Spain","Spain","Spain","Spain","Spain"
],
"my_network": ["Ireland","Austria",None,"Sweden","Italy",None , #France
"Ireland","Austria","Denmark","Sweden",None,"United Kingdom" #Spain
]})#Netherlands
Map4 = pd.DataFrame({
"partner_country": ["France","France","France","France","France","France",
"Spain","Spain","Spain","Spain","Spain","Spain"
],
"my_network": [None,None,None,None,"Italy",None , #France
None,"Austria",None,"Sweden",None,"United Kingdom" #Spain
]})#Netherlands
我想从 Map3 数据框中删除 Map3 和 Map4 中常见的所有观察结果。尝试了以下代码:
Map4[~(Map4['partner_country'].isin(Map3['partner_country'])Map4['my_network'].isin(Map3['my_network']]
一个简单的解决方案,因为您只有 2 列可能是:
common = (Map3.partner_country + Map3.my_network).isin(Map4.partner_country + Map4.my_network)
Map3 = Map3.loc[~common]