生成特定大小的字符串字节

Question

我有这段代码可以生成 80 个字节的单词 'Administrator' 以输出下面的内容。

 szOperatorName = BitConverter.ToString(data, 45, data.Length - 45); //szOperatorName is set to 'Administrator'
byte[] OperatorName = new byte[80];

Array.Copy(Encoding.ASCII.GetBytes(szOperatorName), OperatorName, System.Math.Min(80,szOperatorName.Length));

输出

41 64 6D 69 6E 69 73 74 72 61 74 6F 72 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 0 0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00=[=131=]

预期输出

41 00 64 00 6d 00 69 00 6e 00 69 00 73 00 74 00 72 00 61 00 74 00 6f 00 72 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00

我已经强调了两者之间的一些主要区别，如果您对获得预期结果有任何帮助，我们将不胜感激

Answer 1

要获得预期的输出，请使用 Unicode 编码来获取字节

Encoding.Unicode.GetBytes(szOperatorName)

测试

byte[] bytes = System.Text.Encoding.Unicode.GetBytes("Administrator");
foreach (var b in bytes)
    Console.WriteLine(b);

. . . .
Array.Copy(bytes, newArr, bytes.Length);

您当前的输出基于 ASCII 编码（显然）

生成特定大小的字符串字节

Generating byte of string in with specific size

c#

hex

byte