将 SQL 数据库中的信息显示到 google 图表

Question

我正在尝试将我的 SQL 数据库中的信息显示到 google 图表中。该项目是一个健康仪表板，我需要在其中显示步数、卡路里等。

我从数据库中获取了信息，但无法循环访问它（相同的信息显示多次）。我认为问题出在 "data.addrows" 代码的某个地方。

php
include('template.php');
$query = /** @lang text */ <<
SELECT * FROM project_healthinfo WHERE id = {$_SESSION['userId']} ORDER BY date DESC
END;
$res = $mysqli->query($query);
$result = $res->fetch_object();
$content = <<<END
                  <!-- Google Chart script starts here -->
                  <!--Load the AJAX API-->



                    // Load the Visualization API and the corechart package.
                    google.charts.load('current', {'packages':['corechart']});

                    // Set a callback to run when the Google Visualization API is loaded.
                    google.charts.setOnLoadCallback(drawChart);

                    // Callback that creates and populates a data table,
                    // instantiates the pie chart, passes in the data and
                    // draws it.
                    function drawChart() {

                      // Create the data table.


                            google.charts.load('current', {'packages':['line']});
                            google.charts.setOnLoadCallback(drawChart);

                         google.charts.load('current', {'packages':['line']});
                      google.charts.setOnLoadCallback(drawChart);

                    function drawChart() {

                      var data = new google.visualization.DataTable();
                      data.addColumn('string', 'Date');
                      data.addColumn('number', 'Steps taken');


                      data.addRows([
                        ['$result->date',  $result->steps],
                        ['$result->date',  $result->steps],
                        ['$result->date',  $result->steps]
                      ]);

                      var options = {
                        chart: {
                          title: ''
                        },
                        width: 550,
                        height: 300
                      };

                      var chart = new google.charts.Line(document.getElementById('steps_chart'));

                      chart.draw(data, google.charts.Line.convertOptions(options));
                    }
                  </script>
                  <!-- Google Chart script ends here -->

Answer 1

您需要将 $content 分成两部分。

$before_result_date = <<<EOS
...
EOS;

$after_result_data = <<<EOQ
...
EOS;

然后之间的部分应该有一个类似这样的循环。

while($result = $mysqli->fetch_object()){                      
   printf("['%s', %s],\n",$result->date, $result->steps);
}

加在一起会是这样的：

include('template.php');
$query = /** @lang text */ <<
SELECT * FROM project_healthinfo WHERE id = 
{$_SESSION['userId']} ORDER BY date DESC
END;

$res = $mysqli->query($query);

print $before_result_date;

while($result = $mysqli->fetch_object()){                      
   printf("['%s', %s],\n",$result->date, $result->steps);
}

print $after_result_date;

应该可以了。

将 SQL 数据库中的信息显示到 google 图表

Display information from SQL database to google chart

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php

mysql

sql

google-visualization