具有附加聚合字段的 Doctrine 实体存储库

Question

我有一个实体 Client，它与一个实体 Contract 有关系。合同有一个字段 amount 和一个字段 payingDelay.

Client.php

/**
 * @ORM\OneToMany(targetEntity="Contract", mappedBy="client")
 * @ORM\JoinColumn(name="contract_id", referencedColumnName="id")
 */
private $contract;

我想显示所有客户的列表，其中包含一些基本的客户字段以及一些计算的（SUM 等）合同信息，如下所示：

name - num contracts    - sum(amounts)  - aggregated risk
John - COUNT(contracts) - SUM(C.amount) - SUM(C.amount * C.payingDelay) 

This is my basic `findClientWithCalculations()` method in `ClientRepository`:

        return $this->createQueryBuilder('CLI')
            ->join('CLI.contract', 'CON')
            ->orderBy('CON.startDate', 'DESC')
            ->getQuery()
            ->getResult();

Is there a way I can add extra columns to this QueryBuilder, even if the final structure doesn't match the structure of a Client object or this must be done outside from a repository?

If not, maybe I can build a custom query in a controller and pass the query result to a twig template to show this structure.

Thank you.

Answer 1

虽然不是微不足道的问题，但问题的表述不正确。我认为实体存储库方法必须始终实现某种 findBy() 方法和 return 该存储库所属实体的对象或对象集合。

实际上，实体存储库方法可以return任何东西，因此可以使用实体存储库方法内部的本机查询来解决这个问题。

例如：

ClientRepository.php:

public function findWithContractStatus($contractStatusShortname)
{
    $em = $this->getEntityManager();

    $clientQuery = "select distinct CLI.id, CLI.name, COUNT(contracts) as ncontracts, SUM(C.amount) as amount from client CLI join contract CON on CON.client_id = CON.id group by CLI.id, CLI.name"

    $rsm = new ResultSetMapping();
    $rsm->addScalarResult('id', 'id');
    $rsm->addScalarResult('name', 'name');
    $rsm->addScalarResult('ncontracts', 'ncontracts');
    $rsm->addScalarResult('amount', 'amount');

    $query = $em->createNativeQuery($clientQuery, $rsm);
    return $query->getResult();
}

这将 return 一个具有给定结构的数组 - id、name、ncontracts、amount - 可以在控制器、twig 模板或任何地方迭代。

具有附加聚合字段的 Doctrine 实体存储库

Doctrine entity repository with additional aggregated fields

entity

doctrine

repository