我正在尝试在 PopUp Menu 中实现 onTap() 函数，但我无法这样做

Question

当我希望 PopMenuItem 中的项目之一执行某些特定任务时。
我尝试了实现，但它没有做任何事情我尝试实现 onTap() 函数，但它给我提供了所需的常量错误。
这是代码

import 'package:flutter/material.dart';
import 'package:ssrpa/ui/forgot_password.dart';
import 'package:ssrpa/admin/admin_page2.dart';

class PopUpMenu extends StatelessWidget {
  VoidCallback onEnable;
  VoidCallback onDisable;
  VoidCallback onDelete;

  PopUpMenu({this.onEnable, this.onDisable, this.onDelete});

  void showMenuSelection(String value) {
    switch (value) {
      case 'Enable':
        onEnable();
        break;
      case 'Disable':
        onDisable();
        break;
      case 'Delete':
        onDelete();
        break;
    // Other cases for other menu options
    }
  }

  @override
  Widget build(BuildContext context) {
    return PopupMenuButton<String>(
      padding: EdgeInsets.zero,
      icon: Icon(Icons.more_vert),
      onSelected: showMenuSelection,
      itemBuilder: (BuildContext context) => <PopupMenuEntry<String>>[
        const PopupMenuItem<String>(
            value: 'Enable User',
            child: ListTile(
                title: Text('Enable User'))),
        const PopupMenuItem<String>(
            value: 'Disable User',
            child: ListTile(
                title: Text('Disable User'))),
        const PopupMenuItem<String>(
            value: 'Delete User',
            child: ListTile(
                title: Text('Delete User')))

      ]
    );
  }
}

当从 PopMenuItem 中选择菜单之一时，我可以调用在其他程序中定义的函数吗？
截图如下。

Answer 1

您在弹出菜单项中发送的值字符串与您的 switch case 不匹配

import 'package:flutter/material.dart';
import 'package:ssrpa/ui/forgot_password.dart';
import 'package:ssrpa/admin/admin_page2.dart';

class PopUpMenu extends StatelessWidget {
  VoidCallback onEnable;
  VoidCallback onDisable;
  VoidCallback onDelete;

  PopUpMenu({this.onEnable, this.onDisable, this.onDelete});

  void showMenuSelection(String value) {
    switch (value) {
      case 'Enable User':
        onEnable();
        break;
      case 'Disable User':
        onDisable();
        break;
      case 'Delete User':
        onDelete();
        break;
    // Other cases for other menu options
    }
  }

  @override
  Widget build(BuildContext context) {
    return PopupMenuButton<String>(
      padding: EdgeInsets.zero,
      icon: Icon(Icons.more_vert),
      onSelected: showMenuSelection,
      itemBuilder: (BuildContext context) => <PopupMenuEntry<String>>[
        const PopupMenuItem<String>(
            value: 'Enable User',
            child: ListTile(
                title: Text('Enable User'))),
        const PopupMenuItem<String>(
            value: 'Disable User',
            child: ListTile(
                title: Text('Disable User'))),
        const PopupMenuItem<String>(
            value: 'Delete User',
            child: ListTile(
                title: Text('Delete User')))

      ]
    );
  }
}

我正在尝试在 PopUp Menu 中实现 onTap() 函数，但我无法这样做

I am trying to implement a onTap() fucntion in PopUpMenu but I am unable to do so

popup

dart

flutter